Mathematics

Grade10

Easy

Question

Identify the option that is NOT a solution to the systems of inequalities.

(-5, 0)
(-5, 1)
(-3, -1)
(-2, -1)

hint Hint:

To be a solution to a system of equations, a point must fall within the common shaded region of all the equations. We check that for all the options and find out the required point.

The correct answer is: (-2, -1)

Step 1 of 1:
Observe that the points (-3,-1), (-5,0), and (-5,1) fall within the common shaded region of the equations.
But the option (-2, -1) is not a solution because it does not fall in the shaded region.
Final Answer:
The right choice is-- a. (-2, -1)

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Identify the option that is NOT a solution to the systems of inequalities.

(-5, 0)(-5, 1)(-3, -1)(-2, -1)

To be a solution to a system of equations, a point must fall within the common shaded region of all the equations. We check that for all the options and find out the required point.

The correct answer is: (-2, -1)

Step 1 of 1:Observe that the points (-3,-1), (-5,0), and (-5,1) fall within the common shaded region of the equations.But the option (-2, -1) is not a solution because it does not fall in the shaded region.Final Answer:The right choice is-- a. (-2, -1)

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(-5, 0)
(-5, 1)
(-3, -1)
(-2, -1)

Step 1 of 1:
Observe that the points (-3,-1), (-5,0), and (-5,1) fall within the common shaded region of the equations.
But the option (-2, -1) is not a solution because it does not fall in the shaded region.
Final Answer:
The right choice is-- a. (-2, -1)

Rewrite this inequality in "y =" form to graph.
3x - 6y > 12

Rewrite this inequality in "y =" form to graph.
3x - 6y > 12