Question
If G is the centroid of triangle ABC,
Find GD.
- 3
- 4
- 5
- 6
Hint:
Gentroid is the intersection point of all the three medians of a triangle.
The correct answer is: 5
Centroid divides a median in the ratio 2:1
Related Questions to study
If G is the centroid of triangle ABC,
Find BG.
BE= 12
If G is the centroid of triangle ABC,
Find BG.
BE= 12
If G is the centroid of triangle ABC,
Find BE.
BG = 4x + 4
BG = 2/3 BE
4x + 4 = 2/3 (7x + 5)
12x + 12 = 14x + 10
2x = 2
x = 1
BE = 7x + 5
= 12
If G is the centroid of triangle ABC,
Find BE.
BG = 4x + 4
BG = 2/3 BE
4x + 4 = 2/3 (7x + 5)
12x + 12 = 14x + 10
2x = 2
x = 1
BE = 7x + 5
= 12
If G is the centroid of triangle ABC,
Find CG
>>>CG was given as 5x+1 and CF can be found in terms of x.
>>>There is no scope to find the value of x.
>>>Hence, we have no way to find the value of CG.
If G is the centroid of triangle ABC,
Find CG
>>>CG was given as 5x+1 and CF can be found in terms of x.
>>>There is no scope to find the value of x.
>>>Hence, we have no way to find the value of CG.
If G is the centroid of triangle ABC,
Find AG
Centroid divides a median in the ratio 2:1
If G is the centroid of triangle ABC,
Find AG
Centroid divides a median in the ratio 2:1
If G is the centroid of triangle ABC,
Find x.
If G is the centroid of triangle ABC,
Find x.
In the given figure:
Compare area of ∆ABE, ∆ACE.
In the given figure:
Compare area of ∆ABE, ∆ACE.
In the given figure:
Find the area of ∆AEC.
Area = × 12 × 5
= 30
In the given figure:
Find the area of ∆AEC.
Area = × 12 × 5
= 30
In the given figure:
Find the area of ∆ABE.
Area of the triangle =
Area = × 12 × 5
Area = 30
In the given figure:
Find the area of ∆ABE.
Area of the triangle =
Area = × 12 × 5
Area = 30
In the given figure:
Find h.
In the given figure:
Find h.
Given vertices of a triangle are A (1, 1) B (11, 8) C (13, 6).Find the midpoints of BC, CA
Given vertices of a triangle are A (1, 1) B (11, 8) C (13, 6).Find the midpoints of BC, CA
The centroid and orthocenter of an equilateral triangle for special segments are ____
The centroid and orthocenter, both are the same in an equilateral triangle for special segments
The centroid and orthocenter of an equilateral triangle for special segments are ____
The centroid and orthocenter, both are the same in an equilateral triangle for special segments