Mathematics
Grade10
Easy

Question

In a basketball match, the equation of the kick is recorded as y equals x squared plus 10 x space plus space 15.
How much height did the ball go after the kick?

  1. 10
  2. 15
  3. 20
  4. 25

hintHint:

In this question, we have to find the height at which the ball will go after kick, if the equation of the kick is recorded as y equals x squared plus 10 x space plus space 15. For this we have to find the equation in standard form. Firstly, we will separate the variables, then add open parentheses 10 over 2 close parentheses squared on both the sides. Later, from the standard form the value of (h, k) is the required height of the ball after kick and the distance the ball reaches to.

The correct answer is: 10


    text  Given equation,  end text y equals x squared plus 10 x plus 15
y minus 15 equals x squared plus 10 x
y minus 15 equals open parentheses x squared plus 10 x close parentheses
text  Adding  end text open parentheses 10 over 2 close parentheses squared text  on both the sides,  end text
y minus 15 plus 25 equals open parentheses x squared plus 10 x plus 25 close parentheses
y plus 10 equals left parenthesis x plus 5 right parenthesis squared
y equals left parenthesis x plus 5 right parenthesis squared minus 10
    The height of the ball after the kick is 10 units and the ball reaches a distance of 25 units from the kick point.

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