_______ is the interest on £ 182 at 11% every year over a period of 12 years.

>>> Principal Amount = $fraction numerator 125 cross times 100 over denominator 5 cross times 7 end fraction$
>>> Principal Amount = 357.14 rupees.

A private lender gives loan at 18% per year in simple interest. The borrower hands over $540 over a period of 3 years in interest. __________ is the amount given on loan.

>>> Principal Amount = $fraction numerator S i m p l e space I n t e r e s t cross times 100 over denominator T i m e cross times r a t e end fraction$
>>> Principal Amount = $fraction numerator 540 cross times 100 over denominator 18 cross times 3 end fraction$
>>> principal amount = 1000.

A private lender gives loan at 18% per year in simple interest. The borrower hands over $540 over a period of 3 years in interest. __________ is the amount given on loan.

__________ would be the rate of interest, if £105 is paid per year on a principal amount of £840.

If £600 is paid as interest towards a loan of £1500 over a period of 8 years, the rate of interest is _________.

If Julie pays £18 per month till 2 years on borrowing £1400, _____ is the rate of interest.

_______ is the interest on £356 principal at 8% per year for 5 years.

Fred borrows £420 from a person at 2.8% per annum and promises to pay it back in 3 years. Determine the total amount to be paid back by him.

>>>Simple Interest = $fraction numerator 420 cross times 3 cross times 2.8 over denominator 100 end fraction$
>>> Simple Interest = 35.28.
>>>Therefore, the total amount that he should return = Simple Interest + Principal Amount.
= 420 + 35.28
= 455.28

Fred borrows £420 from a person at 2.8% per annum and promises to pay it back in 3 years. Determine the total amount to be paid back by him.

______ is the simple interest earned by lending £1600 principal at 7% per annum over a period of 12 years.

>>> $S i m p l e space i n t e r e s t space equals fraction numerator P r i n c i p a l space a m o u n t space cross times T i m e cross times r a t e over denominator 100 end fraction$
>>>Simple Interest = $fraction numerator 1600 cross times 7 cross times 12 over denominator 100 end fraction$
>>> Simple Interest = 1344.

______ is the simple interest earned by lending £1600 principal at 7% per annum over a period of 12 years.

_______ is the interest on £567 at 4% every year over a period of 6 years.

>>> $S i m p l e r space i n t e r e s t space equals space fraction numerator P r i n c i p a l space a m o u n t cross times T i m e cross times R t a e space o f space i n t e r e s t over denominator 100 end fraction$
>>>Simple interest = $fraction numerator 567 cross times 4 cross times 6 over denominator 100 end fraction$
>>>Simple Interest = 130.80

_______ is the interest on £567 at 4% every year over a period of 6 years.

Bob wants to find the principal, if £100 is collected for 1 year by lending at 2% per annum.

A bank lends loan at 8% per year in simple interest. The bank collects £800 over a period of 5 years in interest. __________ is the amount given on loan.

>>> $R a t e space o f space i n t e r e s t space equals space fraction numerator s i m p l e space i n t e r e s t cross times 100 over denominator p r i n c i p a l space a m o u n t cross times t i m e end fraction$
>>> $p r i n c i p a l space a m o u n t space equals space fraction numerator s i m p l e space i n t e r e s t cross times 100 over denominator r a t e space o f space i n t e r e s t cross times t i m e end fraction$
>>>Principal amount = $fraction numerator 800 cross times 100 over denominator 8 cross times 5 end fraction$
>>>Principal amount = 2000.

A bank lends loan at 8% per year in simple interest. The bank collects £800 over a period of 5 years in interest. __________ is the amount given on loan.

__________ is the rate of interest, if £40 is paid per year on a principal amount of £500.

>>> Rate of interest = $fraction numerator 40 cross times 100 over denominator 500 cross times 1 end fraction$
= 8 %.

__________ is the rate of interest, if £40 is paid per year on a principal amount of £500.

>>> Rate of interest = $fraction numerator 40 cross times 100 over denominator 500 cross times 1 end fraction$
= 8 %.

If £200 is paid as interest towards a loan of £1000 over a period of 4 years, the rate of interest is _________.

>>> $R a t e space o f space i n t e r e s t space equals space fraction numerator S i m p l e space i n t e r e s t cross times 100 over denominator t i m e cross times p r i n c i p l e end fraction$ .
>>> Rate of interest = $fraction numerator 200 cross times 100 over denominator 4 cross times 1000 end fraction$
= 5 %

If £200 is paid as interest towards a loan of £1000 over a period of 4 years, the rate of interest is _________.

_______ is the interest on $1200 principal at 2% per year for 10 years.

Paul borrows £330 from a bank at 0.5% per annum and agrees to pay it back in 2 years. Determine the total amount to be paid back by him.