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Mathematics

Algebra

Easy

Question

Simplify $negative 16 b c divided by 24 b$

$\frac{3 b}{2 c}$
$\frac{- 3 b}{2 c}$
$\frac{2 c}{3 b}$
$\frac{- 2 c}{3 b}$

The correct answer is: $fraction numerator negative 2 c over denominator 3 b end fraction$

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