Question
Solve the equation 5.3g + 9 = 2.3g + 15
- 1
- 2
- 3
- 4
Hint:
An equation has a constant, variable and an equal to sign. It has two sides LHS and RHS. A linear equation in one variable is equation with only one variable and in which the highest degree is 1. Here, we have to find the value of unknown value, i.e., x by operating both sides with the same number so that the equation will be balanced.
The correct answer is: 2
In the given question equation is 5.3g+9= 2.3g+15
Here, we have to find the value of g.
Bring all the terms containing variables in one side by operating same numbers on both sides to balance the equation.
Step 1: Subtract 2.3g from the both sides.
5.3g+9-2.3g= 2.3g+15-2.3g
5.3g+9-2.3g= 15
Step 3: Subtract 9 in both the sides.
5.3g+9-2.3g-9= 15-9
5.3g-2.3g= 15-9
Step 4: Operate on the like terms on both sides.
2g= 6
Step 5: Divide both the sides by 2.
![rightwards double arrow fraction numerator 2 g over denominator 2 end fraction equals 6 over 2](data:image/png;base64,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)
![rightwards double arrow g equals 3](data:image/png;base64,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)
So, the value of g for this equation is 3.
Therefore, the correct option is c,i.e., 3.
Like terms are the terms having same variable of same power in which the coefficient may not be the same whereas unlike terms are the terms which don't have same variable. Addition and subtraction are possible in like terms but not in unlike terms.
Related Questions to study
Solve the equation 6 – 6x = 5x – 9x – 2.
Like terms are the terms having same variable of same power in which the coefficient may not be the same whereas unlike terms are the terms which don't have same variable. Addition and subtraction are possible in like terms but not in unlike terms.
Solve the equation 6 – 6x = 5x – 9x – 2.
Like terms are the terms having same variable of same power in which the coefficient may not be the same whereas unlike terms are the terms which don't have same variable. Addition and subtraction are possible in like terms but not in unlike terms.