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Mathematics

Grade6

Easy

Question

Solve the following equation using additive property of equality.
$w minus 4 fraction numerator 3 over denominator 8 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction$

$6 \frac{1}{2}$
6
$6 \frac{7}{8}$
$7 \frac{7}{8}$

The correct answer is: $6 fraction numerator 7 over denominator 8 end fraction$

Step 1:
$w minus 4 fraction numerator 3 over denominator 8 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction$
Using additive property of equality, add ( $4 fraction numerator 3 over denominator 8 end fraction$ ) to both sides
Step 2:
$W minus 4 fraction numerator 3 over denominator 8 end fraction plus 4 fraction numerator 3 over denominator 8 end fraction equals 2 fraction numerator 1 over denominator 2 end fraction plus 4 fraction numerator 3 over denominator 8 end fraction$
Then we get, $w equals 6 fraction numerator 7 over denominator 8 end fraction$

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