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Mathematics

Coordinate-Geometry

Easy

Question

$S u p p o s e space t h a t space t h e space p o i n t s space left parenthesis h comma space k right parenthesis comma space left parenthesis 1 comma space 2 right parenthesis space a n d space left parenthesis – 3 comma space 4 right parenthesis space l i e space o n space t h e space l i n e space L subscript 1. space I f space a space l i n e space L subscript 2 space p a s sin g space t h r o u g h space t h e space p o i n t s space left parenthesis h comma space k right parenthesis space a n d space left parenthesis 4 comma space 3 right parenthesis space i s space p e r p e n d i c u l a r space t o space L subscript 1 comma space t h e n space k over h space e q u a l s minus$

$- \frac{1}{7}$
$\frac{1}{3}$
0
3

The correct answer is: $1 third$

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$text Let end text straight O left parenthesis 0 comma 0 right parenthesis text and end text straight A left parenthesis 0 comma 1 right parenthesis text be two fixed points. Then the locus of a point end text P text such that the perimeter of end text straight triangle AOP text is end text 4 comma i s$

$text Let end text straight O left parenthesis 0 comma 0 right parenthesis text and end text straight A left parenthesis 0 comma 1 right parenthesis text be two fixed points. Then the locus of a point end text P text such that the perimeter of end text straight triangle AOP text is end text 4 comma i s$

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