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Mathematics

Algebra

Easy

Question

The set of all possible real values of a such that the inequality $left parenthesis x minus left parenthesis a minus 1 right parenthesis right parenthesis open parentheses x minus open parentheses a squared plus 2 close parentheses close parentheses less than 0$ holds for all $x element of left parenthesis negative 1 comma 3 right parenthesis$ is

(0,1)
$(\infty, - 1]$
$(- \infty, - 1)$
$(1, \infty)$

The correct answer is: $left parenthesis infinity comma negative 1 right square bracket$

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