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Mathematics

Grade-7

Easy

Question

The value of $7 open parentheses 3 over 4 close parentheses space plus space 7 open parentheses fraction numerator negative 4 over denominator 3 end fraction close parentheses$ is ___________

$\frac{56}{13}$
$\frac{- 49}{12}$
$\frac{12}{49}$
$\frac{- 13}{56}$

hint Hint:

Follow simple BODMASS rule to solve the question.

The correct answer is: $fraction numerator negative 49 over denominator 12 end fraction$

STEP BY STEP SOLUTION
$7 open parentheses 3 over 4 close parentheses space plus space 7 open parentheses fraction numerator negative 4 over denominator 3 end fraction close parentheses space M u l t i p l y i n g space 7 space i n space t h e space b r a c k e t 21 over 4 space plus space open parentheses fraction numerator negative 28 over denominator 3 end fraction close parentheses T a k i n g space L C M space o f space 4 space & space 3 space left parenthesis i. e space 12 right parenthesis fraction numerator 63 minus 112 over denominator 12 end fraction space minus 49 over 12$

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