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Mathematics

Grade10

Easy

Question

Write a quadratic function for the maximum height, if the initial velocity is 150 $fraction numerator f t over denominator s end fraction$ , the initial height is 30 ft.

$2 t^{2} + 5 t + 1$
30t + 150
$- 16 t^{2} + 150 t + 30$
0

hint Hint:

At maximum height the velocity becomes momentarily zero.

The correct answer is: $negative 16 t squared plus 150 t plus 30$

The height of the shot (vertical motion model) = $negative 16 t squared plus v subscript 0 t plus h subscript 0$
$equals negative 16 t squared plus 150 cross times t plus 30$
$equals negative 16 t squared plus 150 t plus 30$
Hence, the correct option is D.

We have, h = ut - 1/2gt².

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