Maths-
General
Easy

Question

On a certain sum of money, the difference between the compound interest for a year payable half-yearly and the simple interest for a year is  16. Find the sum lent out; if the rate of interest in both cases is 8%.

hintHint:

Use the formulae of simple interest and compound interest to find the principal amount.

The correct answer is: 10000 Rupees


    Complete step by step solution:
    Let the sum of money = P
    It is given that rate of interest R = 8% and number of years T = 1
    Also Compound interest - Simple interest = CI - SI  = Rs 16
    We calculate simple interest by the formula S I equals fraction numerator P T R over denominator 100 end fraction…(i)
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have T = 1 years, R = 8%  and P = ?
    On substituting the known values in (i), we get S I equals fraction numerator P cross times 1 cross times 8 over denominator 100 end fraction equals fraction numerator 8 P over denominator 100 end fraction…(ii)
    We calculate compound interest by the formula C I equals P open parentheses 1 plus fraction numerator R over denominator 2 cross times 100 end fraction close parentheses to the power of 2 T end exponent minus P…(iii) payable half yearly
    where P is Principal amount, T is number of years and R is rate of interest
    Here, we have T = 1,R = 8% and P = ?
    On substituting the known values in (iii), we get C I equals P open parentheses 1 plus 8 over 200 close parentheses to the power of 2 cross times 1 end exponent minus P
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell not stretchy rightwards double arrow C I equals P open parentheses 208 over 200 close parentheses squared minus P end cell row cell not stretchy rightwards double arrow C I equals P open parentheses 43264 over 40000 close parentheses minus P end cell end table
    not stretchy rightwards double arrow C I equals fraction numerator 3264 P over denominator 40000 end fraction…(iv)
    We have C I minus S I equals fraction numerator 3264 P over denominator 40000 end fraction minus fraction numerator 8 P over denominator 100 end fraction equals 16
    On further simplifications, we have fraction numerator 6400 P over denominator 4000000 end fraction equals 16
    not stretchy rightwards double arrow 64 P equals 640000
    not stretchy rightwards double arrow P equals 10000 text  Rupees  end text
    Hence the sum of money P = 10000 Rupees.

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