Question
Let f = {(1,1), (2,3), (0,–1), (–1, –3)} be a function from Z to Z defined by f(x) = ax + b, for some integers a, b. Determine a, b.
Hint:
An ordered pair is represented as (INPUT, OUTPUT)
A function from set A to the set B is a relation which associates every element of a set A to unique element of set B.
The correct answer is: a = 2 and b = -1 .
We have given a function from Z to Z
f = {(1,1), (2,3), (0,–1), (–1, –3)}
And also we have given that
f(x) = ax + b
We have to find the value of a and b .
First of all if the f is a function then its points will satisfy f(x) = ax + b
f(1) = 1
f(2) = 3
f(0) = -1
f(-1) = -3
i) (1,1)
f(1) = a (1) + b
1 = a + b
ii) (2,3)
f(2) = a (2) + b
3 = 2a + b
Subtract equation (i) from (ii)
2a – a + b – b = 3 – 1
a = 2
Putting this value in equation (i)
1 = 2 + b
b = 1 – 2
b = -1
Therefore, value of a = 2 and b = -1 .
And also we have given that
We have to find the value of a and b .
First of all if the f is a function then its points will satisfy f(x) = ax + b
Putting this value in equation (i)
Therefore, value of a = 2 and b = -1 .
All functions are relations but all relations are not functions.
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