Question
Babu left one-third of his property to his son, one-fourth to his daughter and the remainder to his wife. If his wife's share is Rs 1,80,000, what was the value of his property?
Hint:
let the Babus property be x ; find the Babu's son and daughters property
Now find the remaining share of property which belongs to his wife and equate it with Rs 1,80,000to get the total value of the property..
The correct answer is: Rs 4,32,000
Ans :- Rs 4,32,000
Explanation :-
Step 1:- calculate the share of son and daughter
Let the total value of Babu’s property be x
Now, share of son = ⅓ of x = x/3
share of Daughter = ¼ of x = x/4
Step 2:- Find share of wife
Remaining value of property = Total - son’s share - daughter’s share
= x - (x/3) -(x/4)
= (2x/3) - (x/4)
= 5x/12
The share of Babu’s wife is 5x/12
Step 3:- equate the share of babu’s wife with Rs 1,80,000 to find total value of babu’s property
∴The total value of babu’s property = Rs 4,32,000
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The equations can be solved in many other ways like substitution
method which is: to eliminate one variable in any one of the
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For the solution of the system of equations above, what is the value of ?
Note:
The equations can be solved in many other ways like substitution
method which is: to eliminate one variable in any one of the
equations with the help of other equation. As we need to find the
value of x, we try to find the value of y in terms of x from one
equation. Then put that value of y in the other equation to get a linear equation in one variable , which is x.