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Maths-

General

Easy

Question

$open parentheses 1 plus tan invisible function application alpha close parentheses open parentheses 1 plus tan invisible function application 4 alpha close parentheses equals 2 comma blank alpha element of open parentheses 0 comma blank pi divided by 16 close parentheses$ then $alpha$ is equal to

$\frac{1}{\sqrt{3}}$
$\sqrt{3}$
$- \frac{1}{\sqrt{3}}$
$- \sqrt{3}$

The correct answer is: $square root of 3$

$255 blank tan invisible function application 40 degree plus square root of 3 tan invisible function application 20 degree tan invisible function application 40 degree$ is equal to
$rightwards double arrow square root of 3 equals fraction numerator tan invisible function application 20 degree plus tan invisible function application 40 degree over denominator 1 minus tan invisible function application 20 degree tan invisible function application 40 degree end fraction$
$rightwards double arrow square root of 3 minus square root of 3 tan invisible function application 20 degree tan invisible function application 40 degree equals tan invisible function application 20 degree plus tan invisible function application 40 degree$
$rightwards double arrow tan invisible function application 20 degree plus tan invisible function application 40 degree plus square root of 3 tan invisible function application 20 degree tan invisible function application 40 degree equals square root of 3$
$rightwards double arrow tan invisible function application A plus tan invisible function application B equals 1 minus tan invisible function application A tan invisible function application B$
$rightwards double arrow tan invisible function application open parentheses A plus B close parentheses equals 1 comma blank i. e. comma blank A plus B equals fraction numerator pi over denominator 4 end fraction$
$o r blank alpha plus 4 alpha equals fraction numerator pi over denominator 4 end fraction comma i. e. comma blank alpha equals fraction numerator pi over denominator 20 end fraction$

Related Questions to study

Let $f open parentheses theta close parentheses equals sin invisible function application theta left parenthesis sin invisible function application theta plus sin invisible function application 3 theta right parenthesis.$ Then $f left parenthesis theta right parenthesis$ is

Let $f open parentheses theta close parentheses equals sin invisible function application theta left parenthesis sin invisible function application theta plus sin invisible function application 3 theta right parenthesis.$ Then $f left parenthesis theta right parenthesis$ is

The value of $tan invisible function application 9 degree minus tan invisible function application 27 degree minus tan invisible function application 63 degree plus tan invisible function application 81 degree blank i s$

The value of $tan invisible function application 9 degree minus tan invisible function application 27 degree minus tan invisible function application 63 degree plus tan invisible function application 81 degree blank i s$

If $blank sin invisible function application x plus cos invisible function application x equals fraction numerator square root of 7 over denominator 2 end fraction blank$ where $blank x element of A comma$ then $tan invisible function application fraction numerator x over denominator 2 end fraction blank$ is equal to

If $blank sin invisible function application x plus cos invisible function application x equals fraction numerator square root of 7 over denominator 2 end fraction blank$ where $blank x element of A comma$ then $tan invisible function application fraction numerator x over denominator 2 end fraction blank$ is equal to

parallel

If $fraction numerator 3 pi over denominator 4 end fraction less than alpha less than pi comma blank$ then $square root of 2 cot invisible function application alpha plus fraction numerator 1 over denominator sin to the power of 2 end exponent invisible function application alpha end fraction end root blank$ is equal to

If $fraction numerator 3 pi over denominator 4 end fraction less than alpha less than pi comma blank$ then $square root of 2 cot invisible function application alpha plus fraction numerator 1 over denominator sin to the power of 2 end exponent invisible function application alpha end fraction end root blank$ is equal to

Hydrogen burns in air with a

Hydrogen burns in air with a

Chemistry-General

Metal hydride on treatment with water gives

Metal hydride on treatment with water gives

Chemistry-General

parallel

Which is used hydrogen generators

Which is used hydrogen generators

Chemistry-General

Assertion:First ionization energy for nitrogen is lower than oxygen.
Reason :Across a period effective nuclear charge decreases.

Assertion:First ionization energy for nitrogen is lower than oxygen.
Reason :Across a period effective nuclear charge decreases.

Chemistry-General

Assertion :Outermost electronic configuration of most electropositive elements is ns² np³.
Reason :ns² np³is stable due to half filled subshell.

Assertion :Outermost electronic configuration of most electropositive elements is ns² np³.
Reason :ns² np³is stable due to half filled subshell.

Physics-General

parallel

Assertion :NO^– ion is isoelectronic with CN^– ion.
Reason :Isoelectronic ions have same number of elelctrons.

Assertion :NO^– ion is isoelectronic with CN^– ion.
Reason :Isoelectronic ions have same number of elelctrons.

Physics-General

Assertion :I.E. of ₇N is more than that of ₈O as well as ₆C.
Reason : This is due to difference in reactivity towards oxygen.

Assertion :I.E. of ₇N is more than that of ₈O as well as ₆C.
Reason : This is due to difference in reactivity towards oxygen.

Physics-General

Assertion :Ground state configuration of Cr is 3d⁵, 4s¹.
Reason : A set of half filled orbitals containing one electron each with their spin parallel provides extra stability to the system.

Assertion :Ground state configuration of Cr is 3d⁵, 4s¹.
Reason : A set of half filled orbitals containing one electron each with their spin parallel provides extra stability to the system.

Physics-General

parallel

Assertion :More is the electron affinity greater is the reducing character.
Reason : Reducing character depends on number of electrons gained.

Assertion :More is the electron affinity greater is the reducing character.
Reason : Reducing character depends on number of electrons gained.

Physics-General

Assertion :Ionization potential across the period is Na < Al < Mg < Si.
Reason : Ionization potential decreases with decrease in atomic size.

Assertion :Ionization potential across the period is Na < Al < Mg < Si.
Reason : Ionization potential decreases with decrease in atomic size.

Physics-General

Assertion :Shielding effect increases as we go down the group.
Reason : More is the number of electrons in the penultimate shell, more is shielding.

Assertion :Shielding effect increases as we go down the group.
Reason : More is the number of electrons in the penultimate shell, more is shielding.

Physics-General

parallel

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