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Maths-

General

Easy

Question

$blank to the power of 2 n end exponent C subscript n plus 1 end subscript plus 2 times to the power of 2 n end exponent C subscript n plus to the power of 2 n end exponent C subscript n minus 1 end subscript$ is equal to

$(2 n + 2) C_{n + 1}$
${(n + 1)}_{n + 1}$
${}^{n}C_{n}$
$(2 n + 1) C_{n}$

hint Hint:

To solve the question we have to use $blank to the power of n C subscript r space end subscript plus to the power of n C subscript r minus 1 end subscript equals to the power of n plus 1 end exponent C subscript r space a n d space to the power of n C subscript r space end subscript plus to the power of n C subscript r plus 1 end subscript equals to the power of n plus 1 end exponent C subscript r plus 1 end subscript$ .

The correct answer is: $left parenthesis 2 n plus 2 right parenthesis C subscript n plus 1 end subscript$

using $blank to the power of n C subscript r space end subscript plus to the power of n C subscript r minus 1 end subscript equals to the power of n plus 1 end exponent C subscript r space a n d space to the power of n C subscript r space end subscript plus to the power of n C subscript r plus 1 end subscript equals to the power of n plus 1 end exponent C subscript r plus 1 end subscript$
$blank to the power of 2 n end exponent C subscript n plus 1 end subscript plus 2 times to the power of 2 n end exponent C subscript n plus to the power of 2 n end exponent C subscript n minus 1 end subscript$
$equals to the power of 2 n end exponent C subscript n plus 1 end subscript plus to the power of 2 n end exponent C subscript n plus to the power of 2 n end exponent C subscript n plus to the power of 2 n end exponent C subscript n minus 1 end subscript equals to the power of 2 n plus 1 end exponent C subscript n plus 1 end subscript plus to the power of 2 n plus 1 end exponent C subscript n equals to the power of 2 n plus 1 end exponent C subscript n plus 1 end subscript$

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