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A bag contains 17 counters marked with numbers 1 to 17 on chits A counter is drawn and replaced A second draw is then made The chance that the number on the counter drawn 1st is even and the second is odd is

  1. fraction numerator 64 over denominator 289 end fraction    
  2. fraction numerator 81 over denominator 289 end fraction    
  3. fraction numerator 72 over denominator 289 end fraction    
  4. fraction numerator 36 over denominator 289 end fraction    

The correct answer is: fraction numerator 72 over denominator 289 end fraction


    No of even no’s equals 8, no of odd no’s equals 9
    Required probability equals fraction numerator 8 subscript C subscript 1 end subscript end subscript over denominator 17 subscript C subscript 1 end subscript end subscript end fraction. fraction numerator 9 subscript C subscript 1 end subscript end subscript over denominator 17 subscript C subscript 1 end subscript end subscript end fraction
    equals fraction numerator 8 over denominator 17 end fraction times fraction numerator 9 over denominator 17 end fraction equals fraction numerator 72 over denominator 289 end fraction

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