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Maths-

General

Easy

Question

A party is arranged of 18 persons who sit along two sides of a long table with 9 chairs on each side. Four men wish to sit on one particular side and three on the other particular side. In how many ways can they be seated -

$\frac{11! 9!}{5! 6!}$
$\frac{11! 9! 9!}{5! 6!}$
11! 4! 3!
None of these

The correct answer is: $fraction numerator 11 factorial 9 factorial 9 factorial over denominator 5 factorial 6 factorial end fraction$

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