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Maths-

General

Easy

Question

A stone thrown upwards, has equation of motion $s equals 490 t minus 49 t to the power of 2 end exponent.$ Then, the maximum height reached by it ,is

24500
12500
12250
25400

The correct answer is: 12250

Given , $s equals 490 t minus 4.9 t to the power of 2 end exponent$
$rightwards double arrow blank fraction numerator d s over denominator d t end fraction equals 490 minus 9.8 t$

A stone is reached the maximum height when $fraction numerator d s over denominator d t end fraction equals 0$

$rightwards double arrow blank 490 minus 9.8 t equals 0 rightwards double arrow t equals 50$

$therefore blank$ Maximum height at $t equals 50$

$blank s equals 490 open parentheses 50 close parentheses minus 4.9 open parentheses 50 close parentheses to the power of 2 end exponent equals 12250$

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