Maths-
General
Easy

Question

Assertion: The point of intersection of the lines
Reason : Skew lines do not intersect.

  1. If both (A) and (R) are true, and (R) is the correct explanation of (A).  
  2. If both (A) and (R) are true but (R) is not the correct explanation of (A).  
  3. If (A) is true but (R) is false.  
  4. If (A) is false but (R) is true.  

The correct answer is: If (A) is false but (R) is true.


    lines are skew lines.

    Related Questions to study

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    Maths-

    Let P, Q and R are points on sides AB, AC and AD of the parallelogram ABCD such that Error converting from MathML to accessible text.and Error converting from MathML to accessible text., where k1, k2 and k3 are non-zero positive scalars
    Assertion(A) : k1, 2k2 and k3 are in harmonic progression if P, Q and R are collinear
    Reason(R) :

    Let P, Q and R are points on sides AB, AC and AD of the parallelogram ABCD such that Error converting from MathML to accessible text.and Error converting from MathML to accessible text., where k1, k2 and k3 are non-zero positive scalars
    Assertion(A) : k1, 2k2 and k3 are in harmonic progression if P, Q and R are collinear
    Reason(R) :
    Maths-General

    General
    Maths-

    Assertion(A): If stack r with rightwards arrow on top equals x stack i with hat on top plus y stack j with hat on top plus z stack k with hat on top then equation stack r with rightwards arrow on top cross times left parenthesis 2 stack i with hat on top minus stack j with hat on top plus 3 stack k with hat on top right parenthesis equals 3 stack i with hat on top plus stack k with hat on top represent a straight line.
    Reason(R): If stack r with rightwards arrow on top equals x stack i with hat on top plus y stack j with hat on top plus z stack k with hat on top, then equation stack r with rightwards arrow on top cross times left parenthesis stack i with hat on top plus 2 stack j with hat on top minus 3 stack k with hat on top right parenthesis equals 2 stack i with hat on top minus stack j with hat on top represent a straight line

    Assertion(A): If stack r with rightwards arrow on top equals x stack i with hat on top plus y stack j with hat on top plus z stack k with hat on top then equation stack r with rightwards arrow on top cross times left parenthesis 2 stack i with hat on top minus stack j with hat on top plus 3 stack k with hat on top right parenthesis equals 3 stack i with hat on top plus stack k with hat on top represent a straight line.
    Reason(R): If stack r with rightwards arrow on top equals x stack i with hat on top plus y stack j with hat on top plus z stack k with hat on top, then equation stack r with rightwards arrow on top cross times left parenthesis stack i with hat on top plus 2 stack j with hat on top minus 3 stack k with hat on top right parenthesis equals 2 stack i with hat on top minus stack j with hat on top represent a straight line

    Maths-General
    General
    Maths-

    Assertion(A): Let A left parenthesis stack a with rightwards arrow on top right parenthesis comma B left parenthesis stack b with rightwards arrow on top right parenthesis and C left parenthesis stack c with rightwards arrow on top right parenthesis be three points such that stack a with rightwards arrow on top equals 2 stack i with hat on top plus stack j with hat on top plus stack k with hat on top comma stack b with rightwards arrow on top equals 3 stack i with hat on top minus stack j with hat on top plus 3 stack k with hat on top and stack c with rightwards arrow on top equals – stack i with hat on top plus 7 stack j with hat on top minus 5 stack k with hat on top then OABC is a tetrahedron.
    Reason(R): Let A left parenthesis stack a with rightwards arrow on top right parenthesis comma B left parenthesis stack b with rightwards arrow on top right parenthesis andC left parenthesis stack c with rightwards arrow on top right parenthesis be three points such that stack a with rightwards arrow on top comma stack b with rightwards arrow on top comma stack c with rightwards arrow on top are non-coplanar, then OABC is a tetrahedron, where O is the origin.

    Assertion(A): Let A left parenthesis stack a with rightwards arrow on top right parenthesis comma B left parenthesis stack b with rightwards arrow on top right parenthesis and C left parenthesis stack c with rightwards arrow on top right parenthesis be three points such that stack a with rightwards arrow on top equals 2 stack i with hat on top plus stack j with hat on top plus stack k with hat on top comma stack b with rightwards arrow on top equals 3 stack i with hat on top minus stack j with hat on top plus 3 stack k with hat on top and stack c with rightwards arrow on top equals – stack i with hat on top plus 7 stack j with hat on top minus 5 stack k with hat on top then OABC is a tetrahedron.
    Reason(R): Let A left parenthesis stack a with rightwards arrow on top right parenthesis comma B left parenthesis stack b with rightwards arrow on top right parenthesis andC left parenthesis stack c with rightwards arrow on top right parenthesis be three points such that stack a with rightwards arrow on top comma stack b with rightwards arrow on top comma stack c with rightwards arrow on top are non-coplanar, then OABC is a tetrahedron, where O is the origin.

    Maths-General
    parallel
    General
    Maths-

    Assertion: If stack a with ̄ on top× stack b with ̄ on top= stack c with ̄ on top× stack d with ̄ on top, and stack a with ̄ on top×stack c with ̄ on top= stack b with ̄ on top× stack d with ̄ on top then stack a with ̄ on topstack d with ̄ on top is perpendicular to stack b with ̄ on topstack c with ̄ on top.
    Reason: If stack r with ̄ on topis perpendicular tostack q with ̄ on topthen stack r with ̄ on top.stack q with ̄ on top= 0

    Assertion: If stack a with ̄ on top× stack b with ̄ on top= stack c with ̄ on top× stack d with ̄ on top, and stack a with ̄ on top×stack c with ̄ on top= stack b with ̄ on top× stack d with ̄ on top then stack a with ̄ on topstack d with ̄ on top is perpendicular to stack b with ̄ on topstack c with ̄ on top.
    Reason: If stack r with ̄ on topis perpendicular tostack q with ̄ on topthen stack r with ̄ on top.stack q with ̄ on top= 0

    Maths-General
    General
    Maths-

    Assertion: Vectors – 2stack i with hat on top+stack j with hat on top + stack k with hat on top, stack i with hat on top–stack j with hat on top+stack k with hat on topand stack i with hat on top+ stack j with hat on top –2stack k with hat on top are coplanar for only two values of .
    Reason: Three vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on topare coplanar if stack a with rightwards arrow on top.(stack b with rightwards arrow on top× stack c with rightwards arrow on top) = stack 0 with rightwards arrow on top.

    Assertion: Vectors – 2stack i with hat on top+stack j with hat on top + stack k with hat on top, stack i with hat on top–stack j with hat on top+stack k with hat on topand stack i with hat on top+ stack j with hat on top –2stack k with hat on top are coplanar for only two values of .
    Reason: Three vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on topare coplanar if stack a with rightwards arrow on top.(stack b with rightwards arrow on top× stack c with rightwards arrow on top) = stack 0 with rightwards arrow on top.

    Maths-General
    General
    Maths-

    Assertion (A): If vector stack a with rightwards arrow on top and stack b with rightwards arrow on topare linearly dependent, then vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on top must be dependent.
    Reason (R): If vector stack a with rightwards arrow on top and stack b with rightwards arrow on top are linearly independent, then vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on top must be linearly independent, where vector stack c with rightwards arrow on top is non-zero.

    Assertion (A): If vector stack a with rightwards arrow on top and stack b with rightwards arrow on topare linearly dependent, then vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on top must be dependent.
    Reason (R): If vector stack a with rightwards arrow on top and stack b with rightwards arrow on top are linearly independent, then vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on top must be linearly independent, where vector stack c with rightwards arrow on top is non-zero.

    Maths-General
    parallel
    General
    Maths-

    Assertion: If in a ABC ; Error converting from MathML to accessible text. = Error converting from MathML to accessible text.Error converting from MathML to accessible text. and Error converting from MathML to accessible text. = Error converting from MathML to accessible text. ; |Error converting from MathML to accessible text.|  |Error converting from MathML to accessible text.|, then the value of cos 2A + cos 2B + cos 2C is – 1.
    Reason: If in ABC, C = 90º, then cos 2A + cos 2B + cos 2C = – 1.

    Assertion: If in a ABC ; Error converting from MathML to accessible text. = Error converting from MathML to accessible text.Error converting from MathML to accessible text. and Error converting from MathML to accessible text. = Error converting from MathML to accessible text. ; |Error converting from MathML to accessible text.|  |Error converting from MathML to accessible text.|, then the value of cos 2A + cos 2B + cos 2C is – 1.
    Reason: If in ABC, C = 90º, then cos 2A + cos 2B + cos 2C = – 1.
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    General
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    If stack a with ̄ on top comma stack b with ̄ on top comma stack c with ̄ on top are noncoplanar vectors and stack r with rightwards arrow on top equals left parenthesis stack a with ̄ on top cross times stack b with ̄ on top right parenthesis cross times left parenthesis stack a with ̄ on top cross times stack c with ̄ on top right parenthesis.
    Assertion: stack r with ̄ on topand stack a with ̄ on top are linearly dependent
    Reason: stack r with rightwards arrow on topis r to each of three stack a with ̄ on top comma stack b with ̄ on top comma & stack c with ̄ on top.

    If stack a with ̄ on top comma stack b with ̄ on top comma stack c with ̄ on top are noncoplanar vectors and stack r with rightwards arrow on top equals left parenthesis stack a with ̄ on top cross times stack b with ̄ on top right parenthesis cross times left parenthesis stack a with ̄ on top cross times stack c with ̄ on top right parenthesis.
    Assertion: stack r with ̄ on topand stack a with ̄ on top are linearly dependent
    Reason: stack r with rightwards arrow on topis r to each of three stack a with ̄ on top comma stack b with ̄ on top comma & stack c with ̄ on top.

    Maths-General
    General
    Maths-

    Maths-General

    parallel
    General
    Maths-

    Assertion(A) : If stack r with rightwards arrow on top equals x stack i with hat on top plus y stack j with hat on top plus z stack k with hat on top then equation stack r with rightwards arrow on top cross times left parenthesis 2 stack i with hat on top minus stack j with hat on top plus 3 stack k with hat on top right parenthesis equals 3 stack i with hat on top plus stack k with hat on top represent a straight line.
    Reason(R) : If stack r with rightwards arrow on top equals x stack i with hat on top plus y stack j with hat on top plus z stack k with hat on top, then equation stack r with rightwards arrow on top cross times left parenthesis stack i with hat on top plus 2 stack j with hat on top minus 3 stack k with hat on top right parenthesis equals 2 stack i with hat on top minus stack j with hat on top represent a straight line

    Assertion(A) : If stack r with rightwards arrow on top equals x stack i with hat on top plus y stack j with hat on top plus z stack k with hat on top then equation stack r with rightwards arrow on top cross times left parenthesis 2 stack i with hat on top minus stack j with hat on top plus 3 stack k with hat on top right parenthesis equals 3 stack i with hat on top plus stack k with hat on top represent a straight line.
    Reason(R) : If stack r with rightwards arrow on top equals x stack i with hat on top plus y stack j with hat on top plus z stack k with hat on top, then equation stack r with rightwards arrow on top cross times left parenthesis stack i with hat on top plus 2 stack j with hat on top minus 3 stack k with hat on top right parenthesis equals 2 stack i with hat on top minus stack j with hat on top represent a straight line

    Maths-General
    General
    Maths-

    Assertion(A) : Let A left parenthesis stack a with rightwards arrow on top right parenthesis comma B left parenthesis stack b with rightwards arrow on top right parenthesis and C left parenthesis stack c with rightwards arrow on top right parenthesis be three points such that stack a with rightwards arrow on top equals 2 stack i with hat on top plus stack j with hat on top plus stack k with hat on top comma stack b with rightwards arrow on top equals 3 stack i with hat on top minus stack j with hat on top plus 3 stack k with hat on top and stack c with rightwards arrow on top equals – stack i with hat on top plus 7 stack j with hat on top minus 5 stack k with hat on top then OABC is a tetrahedron.
    Reason(R) : Let A left parenthesis stack a with rightwards arrow on top right parenthesis comma B left parenthesis stack b with rightwards arrow on top right parenthesis andC left parenthesis stack c with rightwards arrow on top right parenthesis be three points such that stack a with rightwards arrow on top comma stack b with rightwards arrow on top comma stack c with rightwards arrow on top are non-coplanar, then OABC is a tetrahedron, where O is the origin.

    Assertion(A) : Let A left parenthesis stack a with rightwards arrow on top right parenthesis comma B left parenthesis stack b with rightwards arrow on top right parenthesis and C left parenthesis stack c with rightwards arrow on top right parenthesis be three points such that stack a with rightwards arrow on top equals 2 stack i with hat on top plus stack j with hat on top plus stack k with hat on top comma stack b with rightwards arrow on top equals 3 stack i with hat on top minus stack j with hat on top plus 3 stack k with hat on top and stack c with rightwards arrow on top equals – stack i with hat on top plus 7 stack j with hat on top minus 5 stack k with hat on top then OABC is a tetrahedron.
    Reason(R) : Let A left parenthesis stack a with rightwards arrow on top right parenthesis comma B left parenthesis stack b with rightwards arrow on top right parenthesis andC left parenthesis stack c with rightwards arrow on top right parenthesis be three points such that stack a with rightwards arrow on top comma stack b with rightwards arrow on top comma stack c with rightwards arrow on top are non-coplanar, then OABC is a tetrahedron, where O is the origin.

    Maths-General
    General
    Maths-

    Assertion : If stack a with ̄ on top× stack b with ̄ on top= stack c with ̄ on top× stack d with ̄ on top, and stack a with ̄ on top×stack c with ̄ on top= stack b with ̄ on top× stack d with ̄ on top then stack a with ̄ on topstack d with ̄ on top is perpendicular to stack b with ̄ on topstack c with ̄ on top.
    Reason : If stack r with ̄ on topis perpendicular tostack q with ̄ on topthen stack r with ̄ on top.stack q with ̄ on top= 0

    Assertion : If stack a with ̄ on top× stack b with ̄ on top= stack c with ̄ on top× stack d with ̄ on top, and stack a with ̄ on top×stack c with ̄ on top= stack b with ̄ on top× stack d with ̄ on top then stack a with ̄ on topstack d with ̄ on top is perpendicular to stack b with ̄ on topstack c with ̄ on top.
    Reason : If stack r with ̄ on topis perpendicular tostack q with ̄ on topthen stack r with ̄ on top.stack q with ̄ on top= 0

    Maths-General
    parallel
    General
    Maths-

    Assertion : Vectors – 2stack i with hat on top+stack j with hat on top + stack k with hat on top, stack i with hat on top–stack j with hat on top+stack k with hat on topand stack i with hat on top+ stack j with hat on top –2stack k with hat on top are coplanar for only two values of .
    Reason : Three vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on topare coplanar if stack a with rightwards arrow on top.(stack b with rightwards arrow on top× stack c with rightwards arrow on top) = stack 0 with rightwards arrow on top.

    Assertion : Vectors – 2stack i with hat on top+stack j with hat on top + stack k with hat on top, stack i with hat on top–stack j with hat on top+stack k with hat on topand stack i with hat on top+ stack j with hat on top –2stack k with hat on top are coplanar for only two values of .
    Reason : Three vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on topare coplanar if stack a with rightwards arrow on top.(stack b with rightwards arrow on top× stack c with rightwards arrow on top) = stack 0 with rightwards arrow on top.

    Maths-General
    General
    Maths-

    Assertion (A) : If vector stack a with rightwards arrow on top and stack b with rightwards arrow on topare linearly dependent, then vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on top must be dependent.
    Reason (R) : If vector stack a with rightwards arrow on top and stack b with rightwards arrow on top are linearly independent, then vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on top must be linearly independent, where vector stack c with rightwards arrow on top is non-zero.

    Assertion (A) : If vector stack a with rightwards arrow on top and stack b with rightwards arrow on topare linearly dependent, then vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on top must be dependent.
    Reason (R) : If vector stack a with rightwards arrow on top and stack b with rightwards arrow on top are linearly independent, then vectors stack a with rightwards arrow on top, stack b with rightwards arrow on top, stack c with rightwards arrow on top must be linearly independent, where vector stack c with rightwards arrow on top is non-zero.

    Maths-General
    General
    Maths-

    Assertion: If in a ABC ; Error converting from MathML to accessible text. = Error converting from MathML to accessible text.Error converting from MathML to accessible text. and Error converting from MathML to accessible text. = Error converting from MathML to accessible text. ; |Error converting from MathML to accessible text.|  |Error converting from MathML to accessible text.|, then the value of cos 2A + cos 2B + cos 2C is – 1.
    Reason: If in ABC, C = 90º, then cos 2A + cos 2B + cos 2C = – 1.

    Assertion: If in a ABC ; Error converting from MathML to accessible text. = Error converting from MathML to accessible text.Error converting from MathML to accessible text. and Error converting from MathML to accessible text. = Error converting from MathML to accessible text. ; |Error converting from MathML to accessible text.|  |Error converting from MathML to accessible text.|, then the value of cos 2A + cos 2B + cos 2C is – 1.
    Reason: If in ABC, C = 90º, then cos 2A + cos 2B + cos 2C = – 1.
    Maths-General

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