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Question

Each side of square is length 5. The centre of square is (3, 7) and one of the diagonals is parallel to y = x. Then the coordinates of its vertices are

  1. (1, 5) (1, 9) (5, 9) (5, 5)    
  2. (2, 5) (2, 7) (4, 7) (4, 4)    
  3. (2, 5) (2, 6) (3, 5) (3, 6)    
  4. None    

The correct answer is: (1, 5) (1, 9) (5, 9) (5, 5)


    To find the coordinates of vertices of square.
    Let  ABCD  in square
    AB=CD=DA=BC=?
    P=(3,7)
    draw PMAB
    M is mid point of AB
    So, AM=MB=PM=?
    diagonal is parallel to y = x, its sides
    are parallel  a to coordinate axis
     M = (3, 5)
     A= (3 - 2, 5) = (1, 5)
    B = (3 + 2 + 5) = (5, 5)
    C = (3 + 5, 7 + 2) = (8, 9)
    D = (3 - 2, 7 + 2) = (1, 9)

    Therefore, the coordinates of vertices of square are (1, 5) (1, 9) (5, 9) (5, 5).

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