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Question

For 3  r  n nCr + 3 nCr–1 + 3 nCr–2 + nCr–3 is-

  1. n+3Cr  
  2. 2 n+2Cr+2  
  3. 3 n+1Cr+1  
  4. 3 nCr  

The correct answer is: n+3Cr


    Use nCr + nCr–1 = n+1Cr
    nCr + nCr–1 + 2(nCr–1 + nCr–2) + nCr–2 + nCr–3

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