Maths-
General
Easy
Question
Given x = {(2, 7), (3, 9), (5, 13), (0, 3)} be a function from Z to Z defined by f(x) = ax + b for some integral a and b. What are the values of a and b?
The correct answer is: a = 2 and b = 3.
We have given a function from Z to Z
Given x = {(2, 7), (3, 9), (5, 13), (0, 3)}
And also we have given that
f(x) = ax + b
We have to find the value of a and b .
First of all if the f is a function then its points will satisfy f(x) = ax + b
f(2) = 7
f(3) = 9
f(5) = 13
f(0) = 3
i) (2,7)
f(2) = a (2) + b
7 = 2a + b
ii) (3,9)
f(3) = a(3) + b
9 = 3a + b
Subtract equation (i) from (ii)
3a – 2a + b – b = 9 – 7
a = 2
Putting this value in equation (i)
7 = 2(2) + b
b = 7 – 4
b = 3
Therefore, value of a = 2 and b = 3.
We have to find the value of a and b .
First of all if the f is a function then its points will satisfy f(x) = ax + b
Subtract equation (i) from (ii)
Putting this value in equation (i)
Therefore, value of a = 2 and b = 3.
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