Maths-
General
Easy
Question
Graph the function f(x)= -3x2 +12x+5
Hint:
For a quadratic function is in standard form, f(x)=ax2+bx+c.
A vertical line passing through the vertex is called the axis of symmetry for the parabola.
Axis of symmetry x=−b/2a
Vertex The vertex of the parabola is located at a pair of coordinates which we will call (h, k). where h is value of x in axis of symmetry formula and k is f(h).
The correct answer is: (2 , 17)
We have given a function
f(x)= -3x2+12x+5
We have to draw graph of given function,
For drawing graph we will need to find some points on curves
Firstly we will find vertex of the function,
x = -b/2a
= -(12)/2(-3)
= -12 / -6
= 2
The x coordinate of the vertex is the same:
h = 2
The y coordinate of the vertex is :
k = f(h)
k = -3h2 + 12h + 5
k = -3(2)2 + 12(2) + 5
k = -12 + 24 + 5
k = 17
Therefore, the vertex is (2 , 17)
Select a few x values, and plug them into the equation to find the corresponding y values. The x values should be selected around the vertex.
x
y
0
5
1
14
2
17
3
14
4
5
Plot the obtained points and draw the graph
x
y
0
5
1
14
2
17
3
14
4
5
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