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Maths-

General

Easy

Question

If $A equals left curly bracket p colon p equals fraction numerator open parentheses n plus 2 close parentheses open parentheses 2 n to the power of 5 end exponent plus 3 n to the power of 4 end exponent plus 4 n to the power of 3 end exponent plus 5 n to the power of 2 end exponent plus 6 close parentheses over denominator n to the power of 2 end exponent plus 2 n end fraction comma n comma p element of Z to the power of plus end exponent right curly bracket$ then the number of elements in the set $A comma$ is

2
3
4
6

The correct answer is: 4

We have,
$p equals fraction numerator left parenthesis n plus 2 right parenthesis left parenthesis 2 n to the power of 5 end exponent plus 3 n to the power of 4 end exponent plus 4 n to the power of 3 end exponent plus 5 n to the power of 2 end exponent plus 6 right parenthesis over denominator n to the power of 2 end exponent plus 2 n end fraction$
$rightwards double arrow p equals 2 n to the power of 4 end exponent plus 3 n to the power of 3 end exponent plus 4 n to the power of 2 end exponent plus 5 n plus fraction numerator 6 over denominator n end fraction$
Clearly, $p element of Z to the power of plus end exponent blank i f f blank n equals 1 comma blank 2 comma blank 3 comma blank 6.$ So, $A$ has 4 elements

Related Questions to study

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The shaded region in the figure represents

The shaded region in the figure represents
Maths-General

Consider the following statements:
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parallel

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