Maths-
General
Easy

Question

If f left parenthesis x right parenthesis equals fraction numerator e to the power of x plus e to the power of negative x end exponent over denominator 2 end fraction ,then the inverse function of f left parenthesis x right parenthesis text  is  end text

  1. log subscript e invisible function application open parentheses x plus square root of x squared plus 1 end root close parentheses
  2. log subscript e invisible function application square root of x squared plus 1 end root
  3. log subscript e invisible function application open parentheses x plus square root of x squared minus 1 end root close parentheses
  4. log subscript e invisible function application open parentheses x minus square root of x squared minus 1 end root close parentheses

hintHint:

In this question, we have to find the inverse f(x) if f left parenthesis x right parenthesis equals fraction numerator e to the power of x plus e to the power of negative x end exponent over denominator 2 end fraction. Firstly, we will consider f(x) to be y. Then we will solve the equation of getting the value of x from the equation. Further, as we get the value of x we can replace x with f to the power of negative 1 left parenthesis x right parenthesis end exponent and on the other side, y with x.

The correct answer is: log subscript e invisible function application open parentheses x plus square root of x squared minus 1 end root close parentheses


    f left parenthesis x right parenthesis equals y equals fraction numerator e to the power of x plus e to the power of negative x end exponent over denominator 2 end fraction
rightwards double arrow space 2 y space space equals e to the power of x plus e to the power of negative x end exponent
rightwards double arrow space 2 y space space equals e to the power of x plus 1 over e to the power of x
rightwards double arrow space 2 y space space equals fraction numerator e to the power of 2 x end exponent plus 1 over denominator e to the power of x end fraction
L e t space e to the power of x space b e space t. space
T h e n comma space
rightwards double arrow space 2 y space space equals fraction numerator t squared plus 1 over denominator t end fraction
rightwards double arrow 2 y t space space equals t squared plus 1
rightwards double arrow t squared minus 2 y t plus 1 equals space 0
rightwards double arrow t space equals fraction numerator 2 y plus-or-minus square root of 4 y squared minus 4 end root over denominator 2 end fraction space
rightwards double arrow t equals y plus-or-minus square root of y squared minus 1 end root
S u b s t i t u t i n g space b a c k space t space equals e to the power of x
rightwards double arrow e to the power of x equals y plus-or-minus square root of y squared minus 1 end root
P u t t i n n g space log space o n space b o t h space t h e space s i d e s comma space
rightwards double arrow log space e to the power of x equals log space left parenthesis y plus-or-minus square root of y squared minus 1 end root right parenthesis
rightwards double arrow x. space log space e space equals log space left parenthesis y plus-or-minus square root of y squared minus 1 end root right parenthesis
rightwards double arrow x space equals fraction numerator log space left parenthesis y plus-or-minus square root of y squared minus 1 end root right parenthesis over denominator log space e end fraction
rightwards double arrow x space equals log subscript e left parenthesis y plus-or-minus square root of y squared minus 1 end root right parenthesis
C o n s i d e r i n g space p o s i t i v e comma space
rightwards double arrow x space equals log subscript e left parenthesis y plus-or-minus square root of y squared minus 1 end root right parenthesis
rightwards double arrow f to the power of negative 1 end exponent left parenthesis x right parenthesis equals log subscript e left parenthesis x plus-or-minus square root of x squared minus 1 end root right parenthesis

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