Maths-
General
Easy

Question

If n = 10800 then find the total number of divisors of n and the number of even divisors

  1. 60, 48    
  2. 48, 60    
  3. 32, 60    
  4. 60, 32    

hintHint:

We are given a number 10800. We have to find the number of divisors it has. and number of even divisiors it has. Divisior is a number that divides the given number giving zero reminder. We will start with finding the prime factors of the number. We will their power to solve the question.

The correct answer is: 60, 48


    The given number is 10800. We will do following steps to find the answer.
    Step 1: Prime factorisation
    Prime factors means we write the given number in terms of multipliction of smallest prime numbers.
    As the given number is even, we will start with 2.
    10800 = 2 × 5400
    = 2 × 2 × 2700
    = 2 × 2 × 2 × 1350
    = 2 × 2 × 2 × 2 × 675
    = 2 × 2 × 2 × 2 × 3 × 225
    = 2 × 2 × 2 × 2 × 3 × 3 × 75
    = 2 × 2 × 2 × 2 × 3 × 3 × 3 × 25
    = 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5 × 5
    = 24 × 33 × 52
    Step 2: We will collect the powers of all the factors. We will add 1 in them. Then we will multiply them. The final value is the number of divisors the given number has.
    Number of divisors = (4 + 1) × (3 + 1) × (2 + 1)
    = 5 × 4 × 3
    = 60
    So, total number of divisors is 60.
    Step 3:  We will collect the powers of odd factors. We will add them and multiply. We will subtract the value from the total number of divisors to get the even number of divisors.
    Odd number of divisors = (3 + 1) × (2 + 1)
    = 4 × 3
    = 12
    Even divisors = Total number of divisors - Odd number of divisors
    = 60 - 12
    = 48
    So, the number of even divisiors is 48.
    The right option is 60,48

    For such questions, we should know how to find prime factors.

    Related Questions to study

    General
    Chemistry-

    For the combustion of n - octane
    C8H18 + O2 → CO2 + H2O at 25°C (ignoring resonance in CO2)

    For the combustion of n - octane
    C8H18 + O2 → CO2 + H2O at 25°C (ignoring resonance in CO2)

    Chemistry-General
    General
    Maths-

    The lengths of parallel sides of trapezium are in the ratio 7 : 5 and the distance between them is 14cm The area of trapezium is 252 cm².Find the length of its parallel sides.

    For such questions, we should know the formula of area of trapezium.

    The lengths of parallel sides of trapezium are in the ratio 7 : 5 and the distance between them is 14cm The area of trapezium is 252 cm².Find the length of its parallel sides.

    Maths-General

    For such questions, we should know the formula of area of trapezium.

    General
    Maths-

    A so lid piece of metal in the form of a Cuboid of dimes ions 24 cm x 18 cm x 4 cm is melted down and casted into a cube Find length of each edge of cube.

    For such questions, we should know the formulas of volume of different shapes. We have to remember that when any metal piece is melted, it's volume doesn't change. The change is there only in the dimensions of the metal piece.

    A so lid piece of metal in the form of a Cuboid of dimes ions 24 cm x 18 cm x 4 cm is melted down and casted into a cube Find length of each edge of cube.

    Maths-General

    For such questions, we should know the formulas of volume of different shapes. We have to remember that when any metal piece is melted, it's volume doesn't change. The change is there only in the dimensions of the metal piece.

    parallel
    General
    Chemistry-

    Human body is an example

    Human body is an example

    Chemistry-General
    General
    Chemistry-

    It takes 2.56 × 10–3 equivalents of KOH to neutralise 0.1254 g H2XO4. The number of neutrons in X is

    It takes 2.56 × 10–3 equivalents of KOH to neutralise 0.1254 g H2XO4. The number of neutrons in X is

    Chemistry-General
    General
    Chemistry-

    Calculate the weight of iron which will be converted into its oxide by the action of 18g of steam on it.

    Calculate the weight of iron which will be converted into its oxide by the action of 18g of steam on it.

    Chemistry-General
    parallel
    General
    Chemistry-

    AB, A2 and B2 are diatomic molecules. If the bond enthalpies of A2, AB and B2 are in the ratio 1:1:0.5 and the enthalpy of formation of AB from A2 and B2 – 100 kJ mol–1, what is the bond enthalpy of A2</sub

    AB, A2 and B2 are diatomic molecules. If the bond enthalpies of A2, AB and B2 are in the ratio 1:1:0.5 and the enthalpy of formation of AB from A2 and B2 – 100 kJ mol–1, what is the bond enthalpy of A2</sub

    Chemistry-General
    General
    Chemistry-

    The H – H bond energy is 430 kJ mole–1 & Cl – Cl bond energy is 240 kJ mole–1. (capital deltaH)f for HClis – 90kJ. The H – Cl bond energy is about

    The H – H bond energy is 430 kJ mole–1 & Cl – Cl bond energy is 240 kJ mole–1. (capital deltaH)f for HClis – 90kJ. The H – Cl bond energy is about

    Chemistry-General
    General
    Chemistry-

    Entropy change involved in conversion of one mole of liquid water at 373 K to vapour at the same temperature (latent heat of vaporisation of water = 2.257 kJ g–1).

    Entropy change involved in conversion of one mole of liquid water at 373 K to vapour at the same temperature (latent heat of vaporisation of water = 2.257 kJ g–1).

    Chemistry-General
    parallel
    General
    Chemistry-

    The outermost shell electronic configuration 3d5, 4s2 represents

    The outermost shell electronic configuration 3d5, 4s2 represents

    Chemistry-General
    General
    Chemistry-

    Which electronic configuration represents a transition element?

    Which electronic configuration represents a transition element?

    Chemistry-General
    General
    Chemistry-

    The no. of d-electrons present in Fe2+ ions is

    The no. of d-electrons present in Fe2+ ions is

    Chemistry-General
    parallel
    General
    Chemistry-

    100 ml of 0.3 N HCl solution were mixed with 200 ml of 0.6 N H2SO4 solution. The final normality of mixture is

    100 ml of 0.3 N HCl solution were mixed with 200 ml of 0.6 N H2SO4 solution. The final normality of mixture is

    Chemistry-General
    General
    Chemistry-

    How many moles of electron is needed for the reduction of each mole of Cr in the reaction.
    CrO5 + H2SO4 ⟶ Cr2(SO4)3 + H2O + O2

    How many moles of electron is needed for the reduction of each mole of Cr in the reaction.
    CrO5 + H2SO4 ⟶ Cr2(SO4)3 + H2O + O2

    Chemistry-General
    General
    Chemistry-

    125 ml of Na2CO3 solution requires 100 ml of 0.1 N HCl to reach end point with phenolphthalein as indicator. Molarity of resulting solution with respect to H C O subscript 3 end subscript superscript minus end superscript ion

    125 ml of Na2CO3 solution requires 100 ml of 0.1 N HCl to reach end point with phenolphthalein as indicator. Molarity of resulting solution with respect to H C O subscript 3 end subscript superscript minus end superscript ion

    Chemistry-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.