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Maths-

General

Easy

Question

If P = (0,1), Q= (0,-1) and R = (0,2) then the locus of the point S such that $S Q to the power of 2 end exponent plus S R to the power of 2 end exponent equals 2 S P to the power of 2 end exponent text end text$ is a

straight line parallel to x-axis
circle with centre (0,0)
circle through (0,0)
straight line parallel to y-axis

The correct answer is: straight line parallel to x-axis

$x to the power of 2 end exponent plus left parenthesis y plus 1 right parenthesis to the power of 2 end exponent plus x to the power of 2 end exponent plus left parenthesis y minus 2 right parenthesis to the power of 2 end exponent equals 2 open square brackets x to the power of 2 end exponent plus left parenthesis y minus 1 right parenthesis to the power of 2 end exponent close square brackets$

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If the distance from P to the points (5, -4), (7, 6) are in the ratio 2 : 3, then the locus of P is

Let $blank A equals open curly brackets A subscript 1 end subscript comma A subscript 2 end subscript comma A subscript 3 end subscript comma A subscript 4 end subscript comma A subscript 5 end subscript comma A subscript 6 end subscript close curly brackets$ be the set of six unit circles with centres $C subscript 1 end subscript comma C subscript 2 end subscript comma C subscript 3 end subscript horizontal ellipsis C subscript 6 end subscript$ arranged as shown in the diagram. The relation R on A is defined by $open parentheses A subscript i end subscript comma A subscript j end subscript close parentheses element of R left right double arrow C subscript i end subscript C subscript j end subscript less or equal than 2 square root of 2 text end text$ then
<img src="https://mycourses.turito.com/tokenpluginfile.php/c161933dbfaab094c54655ab71e9b8f0/1/question/questiontext/655383/1/1167938/Picture1.png" alt="" width="98" height="79"

Let $blank A equals open curly brackets A subscript 1 end subscript comma A subscript 2 end subscript comma A subscript 3 end subscript comma A subscript 4 end subscript comma A subscript 5 end subscript comma A subscript 6 end subscript close curly brackets$ be the set of six unit circles with centres $C subscript 1 end subscript comma C subscript 2 end subscript comma C subscript 3 end subscript horizontal ellipsis C subscript 6 end subscript$ arranged as shown in the diagram. The relation R on A is defined by $open parentheses A subscript i end subscript comma A subscript j end subscript close parentheses element of R left right double arrow C subscript i end subscript C subscript j end subscript less or equal than 2 square root of 2 text end text$ then
<img src="https://mycourses.turito.com/tokenpluginfile.php/c161933dbfaab094c54655ab71e9b8f0/1/question/questiontext/655383/1/1167938/Picture1.png" alt="" width="98" height="79"

The relation R is defined by $R equals left curly bracket left parenthesis a comma b right parenthesis colon b equals vertical line a plus 1 vertical line text end text$ and $blank vertical line a vertical line less or equal than 3 comma a comma b element of Z right curly bracket$ then range of R =

The relation R is defined by $R equals left curly bracket left parenthesis a comma b right parenthesis colon b equals vertical line a plus 1 vertical line text end text$ and $blank vertical line a vertical line less or equal than 3 comma a comma b element of Z right curly bracket$ then range of R =

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