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If sin invisible function application 6 theta plus sin invisible function application 4 theta plus sin invisible function application 2 theta equals 0 comma then theta blankis equal toblank open parentheses n element of Z close parentheses

  1. fraction numerator n pi over denominator 4 end fraction blank o r blank n pi plus-or-minus fraction numerator pi over denominator 3 end fraction  
  2. fraction numerator n pi over denominator 4 end fraction blank o r blank n pi plus-or-minus fraction numerator pi over denominator 6 end fraction  
  3. fraction numerator n pi over denominator 4 end fraction blank o r blank 2 n pi plus-or-minus fraction numerator pi over denominator 6 end fraction  
  4. None of these  

The correct answer is: fraction numerator n pi over denominator 4 end fraction blank o r blank n pi plus-or-minus fraction numerator pi over denominator 3 end fraction


    sin invisible function application 6 theta plus sin invisible function application 4 theta plus sin invisible function application 2 theta equals 0
    rightwards double arrow open parentheses sin invisible function application 6 theta plus sin invisible function application 2 theta close parentheses plus sin invisible function application 4 theta equals 0
    rightwards double arrow 2 sin invisible function application 4 theta cos invisible function application 2 theta plus sin invisible function application 4 theta equals 0
    rightwards double arrow sin invisible function application 4 theta open parentheses 2 cos invisible function application 2 theta plus 1 close parentheses equals 0
    rightwards double arrow sin invisible function application 4 theta equals 0 or cos invisible function application 2 theta equals negative fraction numerator 1 over denominator 2 end fraction equals cos invisible function application fraction numerator 2 pi over denominator 3 end fraction
    rightwards double arrow 4 theta equals n pi blank o r blank 2 theta equals 2 n pi plus-or-minus fraction numerator 2 pi over denominator 3 end fraction comma n element of Z
    rightwards double arrow theta equals fraction numerator n pi over denominator 4 end fraction orblank theta equals n pi plus-or-minus fraction numerator pi over denominator 3 end fraction

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