Question
If the bisector of angle A of a DABC meets BC at D and AB=c,BC=a CA=b then D divides BC in the ratio…
- b:c
- c:b
- a:b
- b:a
Hint:
The given question is about angle bisector. We are given a ∆ABC. The bisector is of ∠A. It cuts the opposite side BC in two parts. We have to find the ratio. We are given the lengt of all three sides. We will use the properties of angle bisector to solve the question.
The correct answer is: c:b
The given values are as follows:
In ∆ABC
∠A is bisected. AD is the biscetor.
AD meets the side BC at point D. Let the part BD be x and DC be y. We have to the ratio x:y.
Length of side AB = c
Length of side AC = b
Length of side BC = a
We will use angle bisector theorem to solve the question.
Angle biscetor states that, " When a line bisceting the angle meets the opposite side at a point, it divides the side in the ratio of other two sides".
In this triangle,
Therefore, the ratio of the side is c:b
For such questions, we should know about angle bisector properties. While taking ratio, we have to careful that we are taking ratio of adjacent sides.
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