Question
If the point ,lies in the region corresponding to the acute angle between the lines 2y=x and 4y=x then - .....
Hint:
When a point lies in between the lines. Then, the point satisfy that the product of values with respect to lines should be less than zero.
The correct answer is:
Given That:
If the point ,lies in the region corresponding to the acute angle between the lines 2y=x and 4y=x then:
>>> The joint equation of the two lines x=2y and x=4y becomes:
u ≡ x - 2y = 0 and v ≡ x - 4y = 0 is
u· v = 0, i.e.,
( x - 2y )·( x - 4y ) = 0. i.e.,
x² - 4xy - 2xy + 8y² = 0, i.e.,
S(x, y) ≡ x² - 6xy + 8y² = 0.... (1)
If the point P(a², a) lies in the interior of the acute angle formed by these lines, then the value of S(x, y) at P( x=a², y=a ) is negative, i.e.,
>>> S(a², a) ≡ (a²)² - 6(a²)(a) + 8a² < 0
∴ a² ( a² - 6a + 8 ) < 0
∴ a² - 6a + 8 < 0
∴ ( a - 2 )( a - 4 ) < 0
>>> Therefore, the range of a is (2,4).
u ≡ x - 2y = 0 and v ≡ x - 4y = 0
>>> S(x, y) ≡ x² - 6xy + 8y² = 0
>>> ( a - 2 )( a - 4 ) < 0
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