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If the position vector of one end of the line segment AB be 2 i plus 3 j minus k and the position vector of its middle point be 3 left parenthesis i plus j plus k right parenthesis comma then the position vector of the other end is

  1. 4 i plus 3 j plus 5 k    
  2. 4 i minus 3 j plus 7 k    
  3. 4 i plus 3 j plus 7 k    
  4. 4 i plus 3 j minus 7 k    

The correct answer is: 4 i plus 3 j plus 7 k


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    Trick : By inspection, middle point of 4 i plus 3 j plus 7 k and 2 i plus 3 j minus k is Error converting from MathML to accessible text.

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