Maths-
General
Easy

Question

I f tan invisible function application fraction numerator pi over denominator 9 end fraction comma blank x blank a n d tan invisible function application fraction numerator 5 pi over denominator 18 end fraction are in A.P. and tan invisible function application fraction numerator pi over denominator 9 end fraction comma blank y blank a n d tan invisible function application fraction numerator 7 pi over denominator 18 end fraction are also in A.P., then

  1. 2 x equals y  
  2. x greater than 2  
  3. x equals y  
  4. None of these  

The correct answer is: 2 x equals y


    By the given conditions tan invisible function application fraction numerator pi over denominator 9 end fraction plus tan invisible function application fraction numerator 5 pi over denominator 18 end fraction equals 2 x.
    tan invisible function application fraction numerator pi over denominator 9 end fraction plus tan invisible function application fraction numerator 7 pi over denominator 18 end fraction equals 2 y blank
    rightwards double arrow 2 x equals tan invisible function application 20 degree plus tan invisible function application 50 degree
    equals fraction numerator sin invisible function application 20 degree over denominator cos invisible function application 20 degree end fraction plus fraction numerator sin invisible function application 50 degree over denominator cos invisible function application 50 degree end fraction
    equals fraction numerator sin invisible function application 20 degree blank cos invisible function application 50 degree plus cos invisible function application 20 degree blank sin invisible function application 50 degree over denominator cos invisible function application 20 degree blank cos invisible function application 50 degree end fraction
    equals fraction numerator sin invisible function application 70 degree over denominator cos invisible function application 20 degree blank cos invisible function application 50 degree end fraction
    equals fraction numerator cos invisible function application 20 degree over denominator cos invisible function application 20 degree blank cos invisible function application 50 degree end fraction equals fraction numerator 1 over denominator cos invisible function application 50 degree end fraction equals fraction numerator 1 over denominator sin invisible function application 40 degree end fraction equals c o s e c blank 40 degree
    2 y equals blank tan invisible function application 20 degree plus tan invisible function application 70 degree
    equals fraction numerator sin invisible function application 20 degree over denominator cos invisible function application 20 degree end fraction plus fraction numerator sin invisible function application 70 degree over denominator cos invisible function application 70 degree end fraction
    equals fraction numerator sin invisible function application 90 degree over denominator cos invisible function application 20 degree blank cos invisible function application 70 degree end fraction
    equals fraction numerator 1 over denominator cos invisible function application 20 degree cos invisible function application 70 degree end fraction equals fraction numerator 1 over denominator cos invisible function application 20 degree sin invisible function application 20 degree end fraction
    equals fraction numerator 2 over denominator 2 sin invisible function application 20 degree cos invisible function application 20 degree end fraction equals fraction numerator 2 over denominator sin invisible function application 40 degree end fraction equals 2 blank c o s e c blank 40 degree
    therefore 2 y equals 2 open parentheses 2 x close parentheses rightwards double arrow y equals 2 x

    Related Questions to study

    General
    Maths-

    Sum of all the solutions in open square brackets 0 comma blank 4 pi close square brackets of the equation tan invisible function application x plus cot invisible function application x plus 1 equals cos invisible function application open parentheses x plus fraction numerator pi over denominator 4 end fraction close parentheses is

    Sum of all the solutions in open square brackets 0 comma blank 4 pi close square brackets of the equation tan invisible function application x plus cot invisible function application x plus 1 equals cos invisible function application open parentheses x plus fraction numerator pi over denominator 4 end fraction close parentheses is

    Maths-General
    General
    Maths-

    Ifblank open parentheses 1 minus tan invisible function application theta close parentheses open parentheses 1 plus tan invisible function application theta close parentheses sec to the power of 2 end exponent invisible function application theta plus 2 to the power of tan to the power of 2 end exponent invisible function application theta end exponent equals 0 comma then the number of values of theta in the interval left parenthesis negative pi divided by 2 comma blank pi divided by 2 right parenthesis are

    Ifblank open parentheses 1 minus tan invisible function application theta close parentheses open parentheses 1 plus tan invisible function application theta close parentheses sec to the power of 2 end exponent invisible function application theta plus 2 to the power of tan to the power of 2 end exponent invisible function application theta end exponent equals 0 comma then the number of values of theta in the interval left parenthesis negative pi divided by 2 comma blank pi divided by 2 right parenthesis are

    Maths-General
    General
    Maths-

    If open vertical bar 2 sin invisible function application theta minus c o s e c blank theta close vertical bar greater or equal than 1 and theta not equal to fraction numerator n pi over denominator 2 end fraction comma blank n element of I, then

    If open vertical bar 2 sin invisible function application theta minus c o s e c blank theta close vertical bar greater or equal than 1 and theta not equal to fraction numerator n pi over denominator 2 end fraction comma blank n element of I, then

    Maths-General
    parallel
    General
    Maths-

    If S equals open curly brackets x element of N blank colon 2 plus log subscript 2 end subscript invisible function application square root of x plus 1 end root greater than 1 minus log subscript 1 divided by 2 end subscript invisible function application square root of 4 minus x to the power of 2 end exponent end root close curly brackets comma then

    If S equals open curly brackets x element of N blank colon 2 plus log subscript 2 end subscript invisible function application square root of x plus 1 end root greater than 1 minus log subscript 1 divided by 2 end subscript invisible function application square root of 4 minus x to the power of 2 end exponent end root close curly brackets comma then

    Maths-General
    General
    Maths-

    log subscript 4 end subscript invisible function application 18 is

    log subscript 4 end subscript invisible function application 18 is

    Maths-General
    General
    Maths-

    If sin invisible function application 6 theta plus sin invisible function application 4 theta plus sin invisible function application 2 theta equals 0 comma then theta blankis equal toblank open parentheses n element of Z close parentheses

    If sin invisible function application 6 theta plus sin invisible function application 4 theta plus sin invisible function application 2 theta equals 0 comma then theta blankis equal toblank open parentheses n element of Z close parentheses

    Maths-General
    parallel
    General
    Maths-

    The area of the circle and the area of a regular polygon of n sides and of perimeter equal to that of the circle are in the ratio of

    The area of the circle and the area of a regular polygon of n sides and of perimeter equal to that of the circle are in the ratio of

    Maths-General
    General
    Maths-

    I f blank x element of open parentheses pi comma fraction numerator 3 pi over denominator 2 end fraction close parentheses comma blank t h e n blank 4 cos to the power of 2 end exponent invisible function application open parentheses fraction numerator pi over denominator 4 end fraction minus fraction numerator x over denominator 2 end fraction close parentheses plus square root of 4 sin to the power of 4 end exponent invisible function application x plus sin to the power of 2 end exponent invisible function application 2 x end root is always equal to

    I f blank x element of open parentheses pi comma fraction numerator 3 pi over denominator 2 end fraction close parentheses comma blank t h e n blank 4 cos to the power of 2 end exponent invisible function application open parentheses fraction numerator pi over denominator 4 end fraction minus fraction numerator x over denominator 2 end fraction close parentheses plus square root of 4 sin to the power of 4 end exponent invisible function application x plus sin to the power of 2 end exponent invisible function application 2 x end root is always equal to

    Maths-General
    General
    Maths-

    If tan invisible function application theta plus sin invisible function application theta equals m blank a n d tan invisible function application theta minus sin invisible function application theta equals n comma then

    If tan invisible function application theta plus sin invisible function application theta equals m blank a n d tan invisible function application theta minus sin invisible function application theta equals n comma then

    Maths-General
    parallel
    General
    Maths-

    I f blank x subscript 1 end subscript blank a n d blank x subscript 2 end subscript are two distinct roots of the equation a cos invisible function application x plus b sin invisible function application x equals c comma blank t h e n tan invisible function application fraction numerator x subscript 1 end subscript plus x subscript 2 end subscript over denominator 2 end fraction is equal to

    I f blank x subscript 1 end subscript blank a n d blank x subscript 2 end subscript are two distinct roots of the equation a cos invisible function application x plus b sin invisible function application x equals c comma blank t h e n tan invisible function application fraction numerator x subscript 1 end subscript plus x subscript 2 end subscript over denominator 2 end fraction is equal to

    Maths-General
    General
    Maths-

    I f fraction numerator sin invisible function application open parentheses x plus y close parentheses over denominator sin invisible function application open parentheses x minus y close parentheses end fraction equals fraction numerator a plus b over denominator a minus b end fraction comma blank t h e n fraction numerator tan invisible function application x over denominator tan invisible function application y end fraction blank i s blank e q u a l blank t o

    I f fraction numerator sin invisible function application open parentheses x plus y close parentheses over denominator sin invisible function application open parentheses x minus y close parentheses end fraction equals fraction numerator a plus b over denominator a minus b end fraction comma blank t h e n fraction numerator tan invisible function application x over denominator tan invisible function application y end fraction blank i s blank e q u a l blank t o

    Maths-General
    General
    Maths-

    Which of the following is not the general solution of 2 to the power of cos invisible function application 2 x end exponent plus 1 equals 3.2 to the power of negative sin to the power of 2 end exponent invisible function application x end exponent ?

    Which of the following is not the general solution of 2 to the power of cos invisible function application 2 x end exponent plus 1 equals 3.2 to the power of negative sin to the power of 2 end exponent invisible function application x end exponent ?

    Maths-General
    parallel
    General
    Maths-

    In triangle A B C comma base B C and area of triangle increment are fixed. Locus of the centroid of triangle A B C is a straight line that is

    In triangle A B C comma base B C and area of triangle increment are fixed. Locus of the centroid of triangle A B C is a straight line that is

    Maths-General
    General
    Maths-

    The radii r subscript 1 end subscript comma blank r subscript 2 end subscript comma blank r subscript 3 end subscript of the escribed circles of the triangle A B C are in H.P. If the area of the triangle is 24 c m to the power of 2 end exponent and its perimeter is 24 cm, then the length of its largest side is

    The radii r subscript 1 end subscript comma blank r subscript 2 end subscript comma blank r subscript 3 end subscript of the escribed circles of the triangle A B C are in H.P. If the area of the triangle is 24 c m to the power of 2 end exponent and its perimeter is 24 cm, then the length of its largest side is

    Maths-General
    General
    Maths-

    In an acute angled triangle A B C comma blank r plus r subscript 1 end subscript equals r subscript 2 end subscript plus r subscript 3 end subscript blankandblank angle B greater than fraction numerator pi over denominator 3 end fraction comma then

    In an acute angled triangle A B C comma blank r plus r subscript 1 end subscript equals r subscript 2 end subscript plus r subscript 3 end subscript blankandblank angle B greater than fraction numerator pi over denominator 3 end fraction comma then

    Maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.