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Maths-

General

Easy

Question

$I n blank a blank capital delta A B C blank i f blank 2 R plus r equals r subscript 1 end subscript comma blank t h e n$

$∠ C = \frac{π}{2}$
$∠ B = \frac{π}{2}$
$∠ A = \frac{π}{2}$
$N o n e o f t h e s e$

The correct answer is: $angle A equals fraction numerator pi over denominator 2 end fraction$

$H i n t colon blank fraction numerator a b c over denominator 2 capital delta end fraction plus fraction numerator capital delta over denominator s end fraction equals fraction numerator capital delta over denominator s minus a end fraction$
Now,
$fraction numerator a b c over denominator 2 capital delta end fraction equals capital delta open parentheses fraction numerator 1 over denominator s minus a end fraction minus fraction numerator 1 over denominator s end fraction close parentheses rightwards double arrow b c equals 2 left parenthesis s minus b right parenthesis plus left parenthesis s minus c right parenthesis$
$rightwards double arrow a to the power of 2 end exponent equals b to the power of 2 end exponent plus c to the power of 2 end exponent rightwards double arrow capital delta equals angle A equals fraction numerator pi over denominator 2 end fraction$

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$I n blank a blank t r i a n g l e blank A B C comma square root of a plus square root of b minus square root of c blank i s$

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$l n invisible function application a capital delta A B C blank i f blank a to the power of 2 end exponent s i n invisible function application left parenthesis B minus C right parenthesis plus b to the power of 2 end exponent s i n invisible function application left parenthesis C minus A right parenthesis plus c to the power of 2 end exponent s i n invisible function application left parenthesis A minus B right parenthesis equals 0 blank comma blank t h e n text triangle is end text$

$l n invisible function application a capital delta A B C blank i f blank a to the power of 2 end exponent s i n invisible function application left parenthesis B minus C right parenthesis plus b to the power of 2 end exponent s i n invisible function application left parenthesis C minus A right parenthesis plus c to the power of 2 end exponent s i n invisible function application left parenthesis A minus B right parenthesis equals 0 blank comma blank t h e n text triangle is end text$

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Alcohols are ,acidic in nature because hydrogen is attached to oxygen which is an electronegative element. Alcohol is weaker acid than water because $O H to the power of minus end exponent$ ion is more stable than $R minus O to the power of minus end exponent$ ion $R minus 0 to the power of minus end exponent$ is less stable, due to +I effect of the alkyl group., Acidity of alcohols increases with increase:' in ' the stability of acid anion.

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