Maths-
General
Easy

Question

In a triangle ABC if cos A + 2cos B + cos C = 2, the sides of the triangle are in

  1. HP    
  2. GP    
  3. AP    
  4. None of these    

The correct answer is: AP


    cos A + 2 cos B + cos C = 2
    ⇒ cos A + cos C = 2(1 – cos B)
    table row cell rightwards double arrow 2 c o s invisible function application open parentheses fraction numerator A plus C over denominator 2 end fraction close parentheses c o s invisible function application open parentheses fraction numerator A minus C over denominator 2 end fraction close parentheses equals 4 s i n to the power of 2 end exponent invisible function application fraction numerator B over denominator 2 end fraction end cell row cell rightwards double arrow c o s invisible function application fraction numerator A minus C over denominator 2 end fraction equals 2 s i n invisible function application fraction numerator B over denominator 2 end fraction end cell row cell rightwards double arrow c o s invisible function application fraction numerator A minus C over denominator 2 end fraction equals 2 c o s invisible function application fraction numerator A plus C over denominator 2 end fraction end cell row cell rightwards double arrow c o s invisible function application fraction numerator A over denominator 2 end fraction c o s invisible function application fraction numerator C over denominator 2 end fraction plus s i n invisible function application fraction numerator A over denominator 2 end fraction s i n invisible function application fraction numerator C over denominator 2 end fraction equals 2 c o s invisible function application fraction numerator A over denominator 2 end fraction c o s invisible function application fraction numerator C over denominator 2 end fraction minus 2 s i n invisible function application fraction numerator A over denominator 2 end fraction s i n invisible function application fraction numerator C over denominator 2 end fraction end cell row cell rightwards double arrow c o t invisible function application fraction numerator A over denominator 2 end fraction c o t invisible function application fraction numerator C over denominator 2 end fraction equals 3 end cell end table
    table row cell rightwards arrow square root of fraction numerator s left parenthesis s minus a right parenthesis over denominator left parenthesis s minus b right parenthesis left parenthesis s minus c right parenthesis end fraction end root times square root of fraction numerator s left parenthesis s minus c right parenthesis over denominator left parenthesis s minus a right parenthesis left parenthesis s minus b right parenthesis end fraction end root equals 3 end cell row cell rightwards double arrow fraction numerator s over denominator s minus b end fraction equals 3 rightwards double arrow 5 equals 3 s minus 3 b rightwards double arrow 2 s equals 3 b end cell row cell rightwards double arrow a plus c equals 2 b rightwards double arrow a comma b comma c blank a r e blank i n blank A P. end cell end table

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