Maths-
General
Easy

Question

In straight capital delta A B C comma c left parenthesis a cos space B minus b cos space A right parenthesis equals

  1. α2-b2
  2. α2+b2
  3. b2-c2
  4. b2+c2

hintHint:

The angles of the triangle ABC are denoted by A, B, C and the corresponding opposite sides by a, b, c.

The correct answer is: α2-b2


    straight capital delta A B C comma space c left parenthesis a cos space B minus b cos space A right parenthesis
W e space k n o w space t h a t space comma fraction numerator a over denominator sin A end fraction equals fraction numerator b over denominator sin B end fraction equals fraction numerator c over denominator sin C end fraction equals 2 R space semicolon space cos space B space equals space fraction numerator space c squared plus a squared minus b squared over denominator 2 c a end fraction
c left parenthesis a cross times fraction numerator space c squared plus a squared minus b squared over denominator 2 c a end fraction minus b cross times fraction numerator space c squared plus b squared minus a squared over denominator 2 c a end fraction right parenthesis
c a cross times fraction numerator space c squared plus a squared minus b squared over denominator 2 c a end fraction minus c b cross times fraction numerator space c squared plus b squared minus a squared over denominator 2 c a end fraction
fraction numerator space c squared plus a squared minus b squared over denominator 2 end fraction minus fraction numerator space c squared plus b squared minus a squared over denominator 2 end fraction
fraction numerator space c squared plus a squared minus b squared space minus c squared minus b squared plus a squared over denominator 2 end fraction
fraction numerator 2 a squared minus 2 b squared space over denominator 2 end fraction space equals a squared space minus space b squared

    s denotes the semi-perimeter of the triangle ABC, ∆ its area and R the radius of the circle circumscribing the triangle ABC i.e., R is the circum-radius.

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