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Maths-

General

Easy

Question

In the figure, $blank stack A B with bar on top divided by stack C D with bar on top divided by stack E F with bar on top$ If AB = 6 cm, BE = 4cm, CD = 10cm, then EF + EC = ... Cm.

$\frac{15}{4}$
$\frac{20}{3}$
$\frac{125}{12}$
$\frac{4}{15}$

The correct answer is: $fraction numerator 125 over denominator 12 end fraction$

Related Questions to study

In the figure, $angle equals angle A C E D$ , AB = 9cm, AD = 7cm, CD = 8cm and CE = 10cm Then DE = ?

In the figure, $angle equals angle A C E D$ , AB = 9cm, AD = 7cm, CD = 8cm and CE = 10cm Then DE = ?

In the figure, $stack A B with bar on top divided by divided by stack Q R with bar on top blank$ If AB = 3cm, PB = 2cm and PR = 6cm then QR = ? cm.

In the figure, $stack A B with bar on top divided by divided by stack Q R with bar on top blank$ If AB = 3cm, PB = 2cm and PR = 6cm then QR = ? cm.

In the figure, $stack A B with bar on top divided by divided by stack C D with bar on top$ and $stack A C with rightwards arrow on top intersection stack B D with bar on top equals 0 blank$ If OA = 3x – 1, OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC =....units.

Hence AC=12

In the figure, $stack A B with bar on top divided by divided by stack C D with bar on top$ and $stack A C with rightwards arrow on top intersection stack B D with bar on top equals 0 blank$ If OA = 3x – 1, OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC =....units.

Hence AC=12

parallel

Two line segments $stack A B with bar on top$ and $stack C D with bar on top$ intersect at E such that $triangle A C E tilde operator triangle B D E times$ If AE = 4cm, BE = 3cm, CE=6cm and DE = x cm then x = ?

Hence x=2

Two line segments $stack A B with bar on top$ and $stack C D with bar on top$ intersect at E such that $triangle A C E tilde operator triangle B D E times$ If AE = 4cm, BE = 3cm, CE=6cm and DE = x cm then x = ?

Hence x=2

In the figure, AB = BC = CD = DE = EF and AF = AE Then $angle A$ = ?

In the figure, AB = BC = CD = DE = EF and AF = AE Then $angle A$ = ?

In the figure, AB = AC, $angle A equals 48 to the power of ring operator end exponent$ and $angle A C D equals 18 to the power of ring operator end exponent$ Then

Hence BC=CD

In the figure, AB = AC, $angle A equals 48 to the power of ring operator end exponent$ and $angle A C D equals 18 to the power of ring operator end exponent$ Then

Hence BC=CD

parallel

In the figure, ‘x° ’ and ‘y° ’ are two exterior angle measures of DABC Then x° + y° =

Hence x+y>180^o

In the figure, ‘x° ’ and ‘y° ’ are two exterior angle measures of DABC Then x° + y° =

Hence x+y>180^o

In $triangle A B C comma text if end text angle A plus angle B equals 84 to the power of ring operator end exponent comma angle B plus angle C equals 146 to the power of ring operator end exponent$ then $angle B equals$

In $triangle A B C comma text if end text angle A plus angle B equals 84 to the power of ring operator end exponent comma angle B plus angle C equals 146 to the power of ring operator end exponent$ then $angle B equals$

The vectors $stack a with minus on top text and end text stack b with minus on top$ are mutually perpendicular then $stack a with minus on top cross times open curly brackets stack a with minus on top cross times open curly brackets stack a with minus on top cross times open parentheses stack a with minus on top cross times stack b with minus on top close parentheses close curly brackets close curly brackets equals$

The vectors $stack a with minus on top text and end text stack b with minus on top$ are mutually perpendicular then $stack a with minus on top cross times open curly brackets stack a with minus on top cross times open curly brackets stack a with minus on top cross times open parentheses stack a with minus on top cross times stack b with minus on top close parentheses close curly brackets close curly brackets equals$

parallel

If $stack a with minus on top comma stack b with minus on top comma stack c with minus on top$ be the three vectors such that $stack a with minus on top cross times stack b with minus on top equals stack c with minus on top text and end text stack b with bar on top cross times stack c with bar on top equals stack a with bar on top$ then

If $stack a with minus on top comma stack b with minus on top comma stack c with minus on top$ be the three vectors such that $stack a with minus on top cross times stack b with minus on top equals stack c with minus on top text and end text stack b with bar on top cross times stack c with bar on top equals stack a with bar on top$ then

If $stack a with minus on top equals stack i with minus on top plus stack j with minus on top plus stack k with minus on top comma stack b with minus on top equals stack i with minus on top minus stack j with minus on top plus stack k with minus on top$ then $stack i with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack i with minus on top close square brackets plus stack j with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack j with minus on top close square brackets plus stack k with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack k with minus on top close square brackets equals$

If $stack a with minus on top equals stack i with minus on top plus stack j with minus on top plus stack k with minus on top comma stack b with minus on top equals stack i with minus on top minus stack j with minus on top plus stack k with minus on top$ then $stack i with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack i with minus on top close square brackets plus stack j with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack j with minus on top close square brackets plus stack k with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack k with minus on top close square brackets equals$

If $a with minus on top to the power of blank comma b with minus on top to the power of blank comma c with rightwards arrow on top$ represents the reciprocal system of vectors of $stack a with minus on top comma stack b with minus on top comma stack c with minus on top$ then $Error converting from MathML to accessible text.$

If $a with minus on top to the power of blank comma b with minus on top to the power of blank comma c with rightwards arrow on top$ represents the reciprocal system of vectors of $stack a with minus on top comma stack b with minus on top comma stack c with minus on top$ then $Error converting from MathML to accessible text.$

parallel

The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement

The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement

physics-General

The variation of velocity of a particle moving along a straight line is shown in the figure. The distance travelled by the particle in 4s is

The variation of velocity of a particle moving along a straight line is shown in the figure. The distance travelled by the particle in 4s is

physics-General

A ball is thrown vertically upward. Ignoring the air resistance, which one of the following plot represents the velocity-time plot for the period ball remains in air?

A ball is thrown vertically upward. Ignoring the air resistance, which one of the following plot represents the velocity-time plot for the period ball remains in air?

physics-General

parallel

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