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Maths-

General

Easy

Question

In triangle ABC, a : b : c = (1 + x) : 1 : (1 – x) where x  (0, 1). If A = $fraction numerator pi over denominator 2 end fraction$ + C, then x =

$\frac{1}{\sqrt{6}}$
$\frac{1}{2 \sqrt{3}}$
$\frac{1}{\sqrt{7}}$
$\frac{1}{2 \sqrt{7}}$

The correct answer is: $fraction numerator 1 over denominator square root of 7 end fraction$

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