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Maths-

General

Easy

Question

If 1, 2, 3 are respectively the perpendicular from the vertices of a triangle on the opposite side, then 1 2 3 =

$\frac{a^{2} b^{2} c^{2}}{8 R^{2}}$
$\frac{a b c}{8 R^{2}}$
$\frac{a^{2} b^{2} c^{2}}{8 R^{3}}$
$\frac{a b c}{8 R^{3}}$

The correct answer is: $fraction numerator a to the power of 2 end exponent b to the power of 2 end exponent c to the power of 2 end exponent over denominator 8 R to the power of 3 end exponent end fraction$

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