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Question

Let alpha, and beta be the roots of x to the power of 2 end exponent minus x plus p equals 0 and gamma and delta be the root of x to the power of 2 end exponent minus 4 x plus q equals 0. If alpha comma blank beta comma blank a n d blank gamma comma blank delta are in G.P., then the integral values of p and q, respectively, are

  1. negative 2 comma blank minus 32   
  2. negative 2 comma blank 3   
  3. negative 6 comma blank 3   
  4. negative 6 comma blank minus 32  

The correct answer is: negative 2 comma blank minus 32


    alpha comma blank beta are the roots of x to the power of 2 end exponent minus x plus p equals 0. Hence,
    alpha plus beta equals 1
    alpha beta equals p
    gamma comma blank delta are the roots of x to the power of 2 end exponent minus 4 x d plus q equals 0. Hence,
    therefore gamma plus delta equals 4 (3)
    alpha comma blank beta comma blank gamma comma blank delta are in G.P. Let alpha equals a comma blank beta equals a r comma blank gamma equals a r to the power of 2 end exponent comma delta equals a r to the power of 3 end exponent, Substituting these values in Eqs. (1), (2), (3) and (4), we get
    alpha plus a r equals 1 (5)
    a to the power of 2 end exponent r equals p (6)
    a r to the power of 2 end exponent plus a r to the power of 3 end exponent equals 4 (7)
    a to the power of 2 end exponent r to the power of 5 end exponent equals q (8)
    Dividing (7) by (5), we get
    fraction numerator a r to the power of 2 end exponent open parentheses 1 plus r close parentheses over denominator a open parentheses 1 plus r close parentheses end fraction equals fraction numerator 4 over denominator 1 end fraction blank rightwards double arrow blank r to the power of 2 end exponent equals 4 blank rightwards double arrow r equals 2 comma blank minus 2
    open parentheses 5 close parentheses rightwards double arrow blank a equals fraction numerator 1 over denominator 1 plus r end fraction equals fraction numerator 1 over denominator 1 plus 2 end fraction blank o r blank fraction numerator 1 over denominator 1 minus 2 end fraction equals fraction numerator 1 over denominator 3 end fraction blank o r minus 1
    As p is an integer (given), r is also an integer (2 or negative 2). Therefore, from (6), a not equal to 1 divided by 3. Hence, a equals negative 1 and r equals negative 2
    therefore p equals open parentheses negative 1 close parentheses to the power of 2 end exponent cross times open parentheses negative 2 close parentheses equals negative 2
    q equals open parentheses negative 1 close parentheses to the power of 2 end exponent cross times open parentheses negative 2 close parentheses to the power of 5 end exponent equals negative 32

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