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Let f left parenthesis x right parenthesis equals a x plus b where c is a variable coefficient and x greater than fraction numerator 7 over denominator 6 end fraction The value of c such that f(x) touches f to the power of negative 1 end exponent (x), is

  1. 6    
  2. 7    
  3. fraction numerator 16 over denominator 3 end fraction    
  4. fraction numerator 4 over denominator 3 end fraction    

The correct answer is: fraction numerator 16 over denominator 3 end fraction


    f(x) and f to the power of negative 1 end exponent left parenthesis x right parenthesis can only intersect on the line y=x and therefore y=x must be tangent at the comman point of tangency
    3 x to the power of 2 end exponent minus 7 x plus c minus x
    3 x to the power of 2 end exponent minus 8 x plus c equals 0. horizontal ellipsis left parenthesis 1 right parenthesis
    Put D equals 0
    64 minus 12 c equals 0 rightwards double arrow c equals fraction numerator 64 over denominator 12 end fraction equals fraction numerator 16 over denominator 3 end fraction
    1 equals 6 x minus 7 rightwards double arrow x equals fraction numerator 4 over denominator 3 end fraction
    From ((a) put x equals 4 divided by 3 text  to get  end text c equals fraction numerator 16 over denominator 3 end fraction

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