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Maths-

General

Easy

Question

$L subscript t not stretchy rightwards arrow 2 end subscript fraction numerator vertical line x minus 2 vertical line over denominator x minus 2 end fraction$

-1
1
0
2

hint Hint:

In this question, from $open vertical bar x minus 2 close vertical bar equals open curly brackets table attributes columnalign left end attributes row cell x minus 2 comma space space space space i f space x greater or equal than 2 end cell row cell negative left parenthesis x minus 2 right parenthesis comma space i f space x less than 2 end cell end table close$ we will consider (x-2) as value as x=2. Then we will simplify to find the value.

The correct answer is: 1

$space space space space L subscript t not stretchy rightwards arrow 2 end subscript fraction numerator vertical line x minus 2 vertical line over denominator x minus 2 end fraction A s space open vertical bar x minus 2 close vertical bar equals open curly brackets table attributes columnalign left end attributes row cell x minus 2 comma space space space i f space x greater or equal than 2 end cell row cell negative left parenthesis x minus 2 right parenthesis comma space space space i f space x less than 2 end cell end table close W e space w i l l space c o m s d e r equals L subscript t not stretchy rightwards arrow 2 end subscript fraction numerator x minus 2 over denominator x minus 2 end fraction equals L subscript t not stretchy rightwards arrow 2 end subscript space 1 over 1 equals 1.$

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