Maths-
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Easy

Question

L t subscript x not stretchy rightwards arrow 3 end subscript fraction numerator x cubed minus 6 x squared plus 9 x over denominator x squared minus 9 end fraction

  1. 1
  2. 3
  3. 0
  4. 1 third

hintHint:

We can apply L'Hopital's rule, also commonly spelled L'Hospital's rule, whenever direct substitution of a limit yields an indeterminate form. This means that the limit of a quotient of functions (i.e., an algebraic fraction) is equal to the limit of their derivatives.
In this question, we have to find value of L t subscript x not stretchy rightwards arrow 3 end subscript fraction numerator x cubed minus 6 x squared plus 9 x over denominator x squared minus 9 end fraction.

The correct answer is: 0


    L t subscript x not stretchy rightwards arrow 3 end subscript fraction numerator x cubed minus 6 x squared plus 9 x over denominator x squared minus 9 end fraction
    If we put x=3 in the given Function, we get
    L t subscript x not stretchy rightwards arrow 3 end subscript fraction numerator x cubed minus 6 x squared plus 9 x over denominator x squared minus 9 end fraction = L t subscript x not stretchy rightwards arrow 3 end subscript fraction numerator 3 cubed minus 6 cross times 3 squared plus 9 cross times 3 over denominator 3 squared minus 9 end fraction space equals 0 over 0
    Therefore, Factorizing Numerator and Denominator.
    x cubed minus 6 x squared plus 9 x space equals x left parenthesis x minus 3 right parenthesis left parenthesis x minus 3 right parenthesis

    x squared minus 9 equals left parenthesis x minus 3 right parenthesis left parenthesis x plus 3 right parenthesis
    L t subscript x not stretchy rightwards arrow 3 end subscript fraction numerator x left parenthesis x minus 3 right parenthesis left parenthesis x minus 3 right parenthesis over denominator left parenthesis x minus 3 right parenthesis left parenthesis x plus 3 right parenthesis end fraction = L t subscript x not stretchy rightwards arrow 3 end subscript fraction numerator left parenthesis x squared minus 3 x right parenthesis over denominator left parenthesis x plus 3 right parenthesis end fraction
    On substituting, We get 
    L t subscript x not stretchy rightwards arrow 3 end subscript fraction numerator left parenthesis x squared minus 3 x right parenthesis over denominator left parenthesis x plus 3 right parenthesis end fraction = fraction numerator left parenthesis 3 squared minus 3 cross times 3 right parenthesis over denominator left parenthesis 3 plus 3 right parenthesis end fraction= 0

    We can only apply the L’Hospital’s rule if the direct substitution returns an indeterminate form, that means fraction numerator 0 over denominator 0 space end fraction space o r space fraction numerator plus-or-minus infinity over denominator plus-or-minus infinity end fraction.

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