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Maths-

General

Easy

Question

(r1 – r) (r2 – r) (r3 – r) =

R/r
4R2r
4Rr2
4R

The correct answer is: 4Rr2

Related Questions to study

$fraction numerator 1 over denominator r subscript 1 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 2 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 3 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript blank superscript 2 end superscript end fraction$ =

$fraction numerator 1 over denominator r subscript 1 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 2 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 3 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript blank superscript 2 end superscript end fraction$ =

If (a – b) (s – c) = (b – c) (s – a) then r1, r2, r3 are in -

If (a – b) (s – c) = (b – c) (s – a) then r1, r2, r3 are in -

If in a triangle $open parentheses 1 minus fraction numerator r subscript 1 end subscript over denominator r subscript 3 end subscript end fraction close parentheses$ = 2, then the triangle is-

If in a triangle $open parentheses 1 minus fraction numerator r subscript 1 end subscript over denominator r subscript 3 end subscript end fraction close parentheses$ = 2, then the triangle is-

parallel

The angles of a right-angled triangle are in A.P. The ratio of the in-radius and the perimeter is -

The angles of a right-angled triangle are in A.P. The ratio of the in-radius and the perimeter is -

In a ABC, if $fraction numerator R over denominator r end fraction$  2, then the triangle is -

In a ABC, if $fraction numerator R over denominator r end fraction$  2, then the triangle is -

abc =

abc =

parallel

If the altitudes of a triangle be 3, 4, 6 then its in-radius is -

If the altitudes of a triangle be 3, 4, 6 then its in-radius is -

4Rr cos $fraction numerator A over denominator 2 end fraction$ cos $fraction numerator B over denominator 2 end fraction$ cos $fraction numerator C over denominator 2 end fraction$ =

4Rr cos $fraction numerator A over denominator 2 end fraction$ cos $fraction numerator B over denominator 2 end fraction$ cos $fraction numerator C over denominator 2 end fraction$ =

If the area of a triangle is 81 square cm and its perimeter is 27cm then its in-radius in centi-metres is -

If the area of a triangle is 81 square cm and its perimeter is 27cm then its in-radius in centi-metres is -

parallel

(r1 + r2) (r2 + r3) (r3 + r1) =

(r1 + r2) (r2 + r3) (r3 + r1) =

r2 r3 + r3 r1 + r1 r2 =

r2 r3 + r3 r1 + r1 r2 =

If the sides be a, b, c then $fraction numerator r subscript 1 end subscript minus r over denominator a end fraction plus fraction numerator r subscript 2 end subscript minus r over denominator b end fraction$ =

If the sides be a, b, c then $fraction numerator r subscript 1 end subscript minus r over denominator a end fraction plus fraction numerator r subscript 2 end subscript minus r over denominator b end fraction$ =

parallel

In any ABC, cosA + cosB + cosC =

In any ABC, cosA + cosB + cosC =

In any ABC, sinA + sinB + sinC =

In any ABC, sinA + sinB + sinC =

In an equilateral triangle the in-radius and the circum-radius are connected by -

In an equilateral triangle the in-radius and the circum-radius are connected by -

parallel

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