Maths-
General
Easy

Question

L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator sin begin display style space end style a x over denominator x cos space x end fraction

  1. 1
  2. 0
  3. a
  4. none of these

hintHint:

We can apply L'Hopital's rule, also commonly spelled L'Hospital's rule, whenever direct substitution of a limit yields an indeterminate form. This means that the limit of a quotient of functions (i.e., an algebraic fraction) is equal to the limit of their derivatives.
In this question, we have to find value of L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator sin begin display style space end style a x over denominator x cos space x end fraction.

The correct answer is: a


    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator sin begin display style space end style a x over denominator x cos space x end fraction
    We first try substitution:
    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator sin begin display style space end style a x over denominator x cos space x end fraction = L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator sin begin display style space end style 0 over denominator 0 space cross times space cos space 0 end fraction = 0 over 0
    Since the limit is in the form 0 over 0. It is indeterminate—we don’t yet know what is it. We need to do some work to put it in a form where we can determine the limit.
    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator sin begin display style space end style a x over denominator x cos space x end fraction ( L'Hopital's Rule for zero over zero, L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator f left parenthesis x right parenthesis over denominator g left parenthesis x right parenthesis end fractionL t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator f apostrophe left parenthesis x right parenthesis over denominator g apostrophe left parenthesis x right parenthesis end fraction )
    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator a space cos left parenthesis a x right parenthesis over denominator co s space x space minus space x sin space x end fraction  (d(sinax)/dx = a cos(ax) , -sin x)
    On substituting, We get
    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator a space cos left parenthesis a x right parenthesis over denominator co s space x space minus space x sin space x end fraction = a

    We can only apply the L’Hospital’s rule if the direct substitution returns an indeterminate form, that means 0 over 0 space o r space fraction numerator plus-or-minus infinity over denominator plus-or-minus infinity end fraction.

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