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The area bounded by the curve x= aopen parentheses fraction numerator text 1- end text text t end text to the power of 2 end exponent over denominator text 1+ end text text t end text to the power of 2 end exponent end fraction close parentheses, y =blank fraction numerator text 2at end text over denominator text 1+ end text text t end text to the power of 2 end exponent end fraction blankin sq. units is

  1. fraction numerator pi a to the power of 2 end exponent over denominator 2 end fraction    
  2. pi a to the power of 2 end exponent    
  3. fraction numerator pi a to the power of 2 end exponent over denominator 4 end fraction    
  4. fraction numerator 3 pi a to the power of 2 end exponent over denominator 2 end fraction    

The correct answer is: pi a to the power of 2 end exponent


    x equals a open parentheses fraction numerator 1 minus t to the power of 2 end exponent over denominator 1 plus t to the power of 2 end exponent end fraction close parentheses comma blank y equals fraction numerator 2 a t over denominator 1 plus t to the power of 2 end exponent end fraction
    x to the power of 2 end exponent plus y to the power of 2 end exponent equals fraction numerator a to the power of 2 end exponent open parentheses 1 minus t to the power of 2 end exponent close parentheses to the power of 2 end exponent plus 4 a to the power of 2 end exponent t to the power of 2 end exponent over denominator open parentheses 1 plus t to the power of 2 end exponent close parentheses to the power of 2 end exponent end fraction blank
    x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent open parentheses 1 close parentheses blank
    R. A equals pi a to the power of 2 end exponent

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