Maths-
General
Easy

Question

The area bounded by the curves is square root of vertical line x vertical line end root plus square root of vertical line y vertical line end root equals square root of a and x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent (where a greater than 0 right parenthesis is

  1. open parentheses pi minus fraction numerator 2 over denominator 3 end fraction close parentheses a to the power of 2 end exponent text  sq units end text    
  2. open parentheses pi plus fraction numerator 2 over denominator 3 end fraction close parentheses a to the power of 2 end exponent text  sq units end text    
  3. open parentheses pi plus fraction numerator 2 over denominator 3 end fraction close parentheses a to the power of 3 end exponent text  sq units end text    
  4. open parentheses pi minus fraction numerator 2 over denominator 3 end fraction close parentheses a to the power of 3 end exponent text  sq units end text    

The correct answer is: open parentheses pi minus fraction numerator 2 over denominator 3 end fraction close parentheses a to the power of 2 end exponent text  sq units end text


    Related Questions to study

    General
    chemistry-

    The electronic configurations of the element A,B, and C are :given below.

    The bond between and C will be:

    The electronic configurations of the element A,B, and C are :given below.

    The bond between and C will be:

    chemistry-General
    General
    chemistry-

    The electronic configurations of the element A,B, and C are :given below.

    The moleculaformulof the compound formed from Band will be:

    The electronic configurations of the element A,B, and C are :given below.

    The moleculaformulof the compound formed from Band will be:

    chemistry-General
    General
    chemistry-

    The electronic configurations of the element A,B, and C are :given below.

    Stable form of C may be represented by the formula:

    The electronic configurations of the element A,B, and C are :given below.

    Stable form of C may be represented by the formula:

    chemistry-General
    parallel
    General
    chemistry-

    The electronic configurations of the element A,B, and C are :given below.

    Stable form of A may be represented by the formula:

    The electronic configurations of the element A,B, and C are :given below.

    Stable form of A may be represented by the formula:

    chemistry-General
    General
    chemistry-

    Lewis concept of covalency of an element involvesoctetrule.Lateronitwasfoundthatmanyelementsin their compounds, e.g., B e F subscript 2 end subscript comma B F subscript 3 end subscript etc. have incompleteoctetwhereasP C l subscript 5 end subscript comma S F subscript 6 end subscript et c.haveexpandedoctet. This classicaconcept also failed inpredictingthegeometryof molecules. Modem concept of covalence was pro­ posed in terms of valence bond theory. Hybridizationconcept along with valence bond theory successfullexplained the geometryofvariousmoleculesbutfailedin many molecules ThebondangleN O subscript 2 end subscript superscript plus end superscript comma N O subscript 2 end subscriptandN O subscript 2 end subscript superscript minus end superscriptare,respectively:

    Lewis concept of covalency of an element involvesoctetrule.Lateronitwasfoundthatmanyelementsin their compounds, e.g., B e F subscript 2 end subscript comma B F subscript 3 end subscript etc. have incompleteoctetwhereasP C l subscript 5 end subscript comma S F subscript 6 end subscript et c.haveexpandedoctet. This classicaconcept also failed inpredictingthegeometryof molecules. Modem concept of covalence was pro­ posed in terms of valence bond theory. Hybridizationconcept along with valence bond theory successfullexplained the geometryofvariousmoleculesbutfailedin many molecules ThebondangleN O subscript 2 end subscript superscript plus end superscript comma N O subscript 2 end subscriptandN O subscript 2 end subscript superscript minus end superscriptare,respectively:

    chemistry-General
    General
    chemistry-

    NO is a colorless gasandan important intermediate inthemanufactureof nitricacidby catalytic oxidationofammonia. Whichofthefollowingisaneutraloxide?</span

    NO is a colorless gasandan important intermediate inthemanufactureof nitricacidby catalytic oxidationofammonia. Whichofthefollowingisaneutraloxide?</span

    chemistry-General
    parallel
    General
    chemistry-

    NO has11 valence electrons.It is impossible for all1be paired. and hence this is an odd electron molecule,and the gas is paramagnetic. Which of the following species has the smallest N-O bond length?

    NO has11 valence electrons.It is impossible for all1be paired. and hence this is an odd electron molecule,and the gas is paramagnetic. Which of the following species has the smallest N-O bond length?

    chemistry-General
    General
    chemistry-

    Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series. Which has the smallest bond angle left parenthesis X minus S minus X right parenthesis in the given molecules?

    Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series. Which has the smallest bond angle left parenthesis X minus S minus X right parenthesis in the given molecules?

    chemistry-General
    General
    chemistry-

    Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series.

    Consider the following hydrides and arrange them in increasing order of bond ang les:
    I) N H subscript 3 end subscript
    II) P H subscript 3 end subscript
    III) A s H subscript 3 end subscript
    IV) S b H subscript 3 end subscript

    Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series.

    Consider the following hydrides and arrange them in increasing order of bond ang les:
    I) N H subscript 3 end subscript
    II) P H subscript 3 end subscript
    III) A s H subscript 3 end subscript
    IV) S b H subscript 3 end subscript

    chemistry-General
    parallel
    General
    chemistry-

    Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series. Consider the following molecules:
    I) H subscript 2 end subscript O
    II) H subscript 2 end subscript text end text S
    III) H subscript 2 end subscript S e
    IV) H subscript 2 end subscript T e

    Arrange these molecules in increasing order of bond angle:

    Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series. Consider the following molecules:
    I) H subscript 2 end subscript O
    II) H subscript 2 end subscript text end text S
    III) H subscript 2 end subscript S e
    IV) H subscript 2 end subscript T e

    Arrange these molecules in increasing order of bond angle:

    chemistry-General
    General
    chemistry-

    A) 
    B) 
    C) 
    In the thiocyanate ion, S C N to the power of minus end exponent three resonance structures are consistent with the electron -dot method Structure A has only one negative formal charge on the nitrogen atom, the most electro negative atom in the ion. Structure B has a single negative charge on the S, which is less electronegative than N. Structure C has charges of -2 on N and +1 on S, consistent with the relative electronegativities of the atoms but with a larger charge and greater charge separation than the first.
    HNCs is isostructural with:

    A) 
    B) 
    C) 
    In the thiocyanate ion, S C N to the power of minus end exponent three resonance structures are consistent with the electron -dot method Structure A has only one negative formal charge on the nitrogen atom, the most electro negative atom in the ion. Structure B has a single negative charge on the S, which is less electronegative than N. Structure C has charges of -2 on N and +1 on S, consistent with the relative electronegativities of the atoms but with a larger charge and greater charge separation than the first.
    HNCs is isostructural with:

    chemistry-General
    General
    chemistry-

    A) 
    B) 
    C) 
    In the thiocyanate ion, S C N to the power of minus end exponent three resonance structures are consistent with the electron -dot method Structure A has only one negative formal charge on the nitrogen atom, the most electro negative atom in the ion. Structure B has a single negative charge on the S, which is less electronegative than N. Structure C has charges of -2 on N and +1 on S, consistent with the relative electronegativities of the atoms but with a larger charge and greater charge separation than the first. Predict the hybridization of atom which is bonded with H in structure HNCS:

    A) 
    B) 
    C) 
    In the thiocyanate ion, S C N to the power of minus end exponent three resonance structures are consistent with the electron -dot method Structure A has only one negative formal charge on the nitrogen atom, the most electro negative atom in the ion. Structure B has a single negative charge on the S, which is less electronegative than N. Structure C has charges of -2 on N and +1 on S, consistent with the relative electronegativities of the atoms but with a larger charge and greater charge separation than the first. Predict the hybridization of atom which is bonded with H in structure HNCS:

    chemistry-General
    parallel
    General
    chemistry-

    Number of pi bonds sigma bonds in the following structure is:

    Number of pi bonds sigma bonds in the following structure is:

    chemistry-General
    General
    chemistry-

    Which of the following reaction staking place in the blastfurnace during extraction of ironsendo thermic?

    Which of the following reaction staking place in the blastfurnace during extraction of ironsendo thermic?

    chemistry-General
    General
    chemistry-

    Which method of purification is represented by thee quations :

    Which method of purification is represented by thee quations :

    chemistry-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.