Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

The area enclosed within the curve $vertical line x vertical line plus vertical line y vertical line equals 1$ is

$\sqrt{2}$
1
$\sqrt{3}$
2

The correct answer is: 2

The given lines are $plus-or-minus x plus-or-minus y equals 1$
That is ,
$x plus y equals 1 comma x minus y equals 1 comma x plus y equals negative 1 text and end text x minus y equals negative 1$
These lines form a quadrilateral whose vertices are $blank A left parenthesis negative 10 right parenthesis comma B left parenthesis 0 comma negative 1 right parenthesis comma C left parenthesis 10 right parenthesis$ and D(0, 1) Obviously, ABCD is a square. The length of each side of this square is
$square root of 1 to the power of 2 end exponent plus 1 to the power of 2 end exponent end root equals square root of 2$
Hence, the area of square is
$square root of 2 cross times square root of 2 equals 2 text sq. unit end text$
Trick: The required area is
$fraction numerator 2 c to the power of 2 end exponent over denominator vertical line a b vertical line end fraction equals fraction numerator 2 cross times 1 to the power of 2 end exponent over denominator vertical line 1 cross times 1 vertical line end fraction equals 2$

Related Questions to study

Given the four lines with equations $x plus 2 y equals 3 , 3 x plus 4 y equals 7$ $2 x plus 3 y equals 4 text and end text 4 x plus 5 y equals 6$ then these lines are

Given the four lines with equations $x plus 2 y equals 3 , 3 x plus 4 y equals 7$ $2 x plus 3 y equals 4 text and end text 4 x plus 5 y equals 6$ then these lines are

In what direction a line be drawn through the point (1, 2) so that its points of intersection with the line $x plus y equals 4 blank$ is at a distance $square root of 6 divided by 3$ from the given point

In what direction a line be drawn through the point (1, 2) so that its points of intersection with the line $x plus y equals 4 blank$ is at a distance $square root of 6 divided by 3$ from the given point

The equation of perpendicular bisectors of sides AB and AC of a triangle ABC are $x minus y plus 5 equals 0 text and end text x plus 2 y equals 0$ respectively. If point A is (1, -2), then the equation of line BC is

The equation of perpendicular bisectors of sides AB and AC of a triangle ABC are $x minus y plus 5 equals 0 text and end text x plus 2 y equals 0$ respectively. If point A is (1, -2), then the equation of line BC is

parallel

The points $open parentheses 0 comma fraction numerator 8 over denominator 3 end fraction close parentheses comma left parenthesis 1 , 3 right parenthesis text and end text left parenthesis 82 , 30 right parenthesis$

The points $open parentheses 0 comma fraction numerator 8 over denominator 3 end fraction close parentheses comma left parenthesis 1 , 3 right parenthesis text and end text left parenthesis 82 , 30 right parenthesis$

If the lines joining the origin to the points of intersection of the line 3y = mx + 3 and the curve $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 1$ are at right angle, then value of m + 3 is equal to

If the lines joining the origin to the points of intersection of the line 3y = mx + 3 and the curve $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 1$ are at right angle, then value of m + 3 is equal to

If, for a positive integer n, the quadratic equation $x left parenthesis x plus 1 right parenthesis plus left parenthesis x plus 1 right parenthesis left parenthesis x plus 2 right parenthesis plus horizontal ellipsis plus left parenthesis x plus stack n minus 1 with bar on top right parenthesis left parenthesis x plus n right parenthesis equals 10 n$ has two consecutive integral solutions, then n is equal to

If, for a positive integer n, the quadratic equation $x left parenthesis x plus 1 right parenthesis plus left parenthesis x plus 1 right parenthesis left parenthesis x plus 2 right parenthesis plus horizontal ellipsis plus left parenthesis x plus stack n minus 1 with bar on top right parenthesis left parenthesis x plus n right parenthesis equals 10 n$ has two consecutive integral solutions, then n is equal to

parallel

If n is even, then in the expansion of $open parentheses 1 plus fraction numerator x to the power of 2 end exponent over denominator 2 factorial end fraction plus fraction numerator x to the power of 4 end exponent over denominator 4 factorial end fraction plus midline horizontal ellipsis close parentheses to the power of 2 end exponent$ , the coefficient of $x to the power of n end exponent text is end text$

If n is even, then in the expansion of $open parentheses 1 plus fraction numerator x to the power of 2 end exponent over denominator 2 factorial end fraction plus fraction numerator x to the power of 4 end exponent over denominator 4 factorial end fraction plus midline horizontal ellipsis close parentheses to the power of 2 end exponent$ , the coefficient of $x to the power of n end exponent text is end text$

The sum to n terms of the series $6 times 9 plus 12 times 21 plus 20 times 37 plus 30 times 57 plus 42 times 81 plus midline horizontal ellipsis$ is

The sum to n terms of the series $6 times 9 plus 12 times 21 plus 20 times 37 plus 30 times 57 plus 42 times 81 plus midline horizontal ellipsis$ is

$text If end text 0 less than alpha less than fraction numerator pi over denominator 2 end fraction text and end text f left parenthesis alpha right parenthesis equals pi to the power of sec to the power of 2 end exponent invisible function application alpha end exponent c o s to the power of 2 end exponent invisible function application alpha plus pi to the power of cosec to the power of 3 end exponent invisible function application alpha end exponent s i n to the power of 2 end exponent invisible function application alpha comma text end text$ then

$text If end text 0 less than alpha less than fraction numerator pi over denominator 2 end fraction text and end text f left parenthesis alpha right parenthesis equals pi to the power of sec to the power of 2 end exponent invisible function application alpha end exponent c o s to the power of 2 end exponent invisible function application alpha plus pi to the power of cosec to the power of 3 end exponent invisible function application alpha end exponent s i n to the power of 2 end exponent invisible function application alpha comma text end text$ then

parallel

When Cl₂ is passed into moist slaked like, compound formed is:

When Cl₂ is passed into moist slaked like, compound formed is:

Chemistry-General

In zone - refining method the molten zone

In zone - refining method the molten zone

Chemistry-General

Ag₂S + NaCN + Zn $⟶$ Ag This method of extraction of Ag by complex formation and then its displacement is called

Ag₂S + NaCN + Zn $⟶$ Ag This method of extraction of Ag by complex formation and then its displacement is called

Chemistry-General

parallel

On igniting Fe₂O₃ at 1400°C, the product obtained is:

On igniting Fe₂O₃ at 1400°C, the product obtained is:

Chemistry-General

AgCl on fusion with Na₂CO₃ form

AgCl on fusion with Na₂CO₃ form

Chemistry-General

As the reaction is increased from T₁ to T₂

As the reaction is increased from T₁ to T₂

Chemistry-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.