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Maths-

General

Easy

Question

The area of a circle is A1 and the area of a regular pentagon inscribed in the circle is A2. Then A1 : A2 is -

$\frac{π}{5}$ cos $\frac{π}{10}$
$\frac{2 π}{5}$ sec $\frac{π}{10}$
$\frac{2 π}{5}$ cosec $\frac{π}{10}$
none of these

The correct answer is: $fraction numerator 2 pi over denominator 5 end fraction$ sec $fraction numerator pi over denominator 10 end fraction$

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16R2 r r1 r2 r3 =

16R2 r r1 r2 r3 =

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