Maths-
General
Easy

Question

The curves a x squared plus b y squared equals 1 and A x to the power of 2 end exponent plus B y to the power of 2 end exponent equals 1 intersect orthogonally, then

  1. fraction numerator 1 over denominator a end fraction plus fraction numerator 1 over denominator A end fraction equals fraction numerator 1 over denominator b end fraction plus fraction numerator 1 over denominator B end fraction    
  2. fraction numerator 1 over denominator a end fraction minus fraction numerator 1 over denominator A end fraction equals fraction numerator 1 over denominator b end fraction minus fraction numerator 1 over denominator B end fraction    
  3. fraction numerator 1 over denominator a end fraction plus fraction numerator 1 over denominator b end fraction equals fraction numerator 1 over denominator B end fraction minus fraction numerator 1 over denominator A end fraction    
  4. fraction numerator 1 over denominator a end fraction minus fraction numerator 1 over denominator A end fraction equals fraction numerator 1 over denominator b end fraction plus fraction numerator 1 over denominator B end fraction    

hintHint:

We are given two curves. They intersect orthogonally. We have to find the relation between the variables.

The correct answer is: fraction numerator 1 over denominator a end fraction minus fraction numerator 1 over denominator A end fraction equals fraction numerator 1 over denominator b end fraction minus fraction numerator 1 over denominator B end fraction


    The curves are as follows:
    ax2 + by2 = 1            ...(1)
    Ax2 + By2 = 1          ...(2)        
    We will take the derivative of equation (1) w.r.t x.
    2ax + 2byfraction numerator d y over denominator d x end fraction=0
    2byfraction numerator d y over denominator d x end fraction= -2ax
    fraction numerator d y over denominator d x end fraction equals fraction numerator negative 2 a x over denominator 2 b y end fraction
    This is this slope of first curve. We will call it slope1.
    In the same way we will take the derivative of equation (2) w.r.t x 
    2Ax + 2Byfraction numerator d y over denominator d x end fraction = 1
    fraction numerator d y over denominator d x end fraction equals fraction numerator negative 2 A x over denominator 2 B y end fraction
    We will call it slope2.
    The two curves are orthogonal. So, the product of their slope is -1.
    Slope1 × Slope2 = -1
    fraction numerator negative 2 a x over denominator 2 b y end fraction cross times fraction numerator negative 2 A x over denominator 2 B y end fraction space equals space minus 1
fraction numerator a A x squared over denominator b B y squared end fraction equals negative 1
space a A x squared space equals space minus b B y squared
space space a x squared space equals fraction numerator negative b B y squared over denominator A end fraction space space space space space space... left parenthesis 3 right parenthesis
space space A x squared space equals space fraction numerator negative b B y squared over denominator a end fraction space space space space... left parenthesis 4 right parenthesis
    We will substitute (3) in (1)
    fraction numerator negative b B over denominator A end fraction y squared plus b y squared equals 1
left parenthesis space fraction numerator negative b B over denominator A end fraction plus b right parenthesis y squared space equals space 1 space space space space space space... left parenthesis 5 right parenthesis
    We will substitute (4) in (2)
    fraction numerator negative b B over denominator a end fraction y squared plus B y squared equals 1
left parenthesis fraction numerator negative b B over denominator a end fraction plus B right parenthesis y squared space equals space 1 space space space space space space space space space space... left parenthesis 6 right parenthesis
    Divide (5) by (6) 
    fraction numerator begin display style fraction numerator negative b B over denominator A end fraction end style plus b over denominator negative begin display style fraction numerator b B over denominator a end fraction end style plus B end fraction space equals space 1
fraction numerator negative b B over denominator A end fraction plus b space equals space fraction numerator negative b B over denominator a end fraction space plus space B
space space D i v i d e space a l l space t h e space s i d e s space b y space B b
space space space space space fraction numerator negative 1 over denominator A end fraction plus 1 over B space equals space fraction numerator negative 1 over denominator a end fraction plus 1 over b
space space space space space space space 1 over a minus 1 over A space equals 1 over b minus 1 over B
    This is the required answer.
     
     
     
    .    

    For such questions, we should be careful while taking the derivative.

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